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choli [55]
3 years ago
14

HG is the perpendicular bisector of FK. What is the length of GH? 8 9 15 34

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
4 0

Answer:

GH=15

Step-by-step explanation:

HK= FK/2= 16/2= 8

Using pythagoras theorem in triangle GHK,

GH²= GK²-HK²

= 17²-8²

= 225

GH= √225

=15

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235or 236

Step-by-step explanation:

A cone has a radius of 5 cm

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Find the area of the shaded region.
kolbaska11 [484]

Answer:

\boxed{ \tt\longrightarrow \: Area \:  Of  \: Shaded \:  region  \: =\boxed{ \tt 39  \: in²}}

Step-by-step explanation:

<u>Given:</u>

The Dimensions of Parallelogram are 12 in.(Base) and 7 in.(Height)

<em>And,</em>

The Dimensions of Rectangle are 9 in.(Length) and 5 in.(Breadth).

<u>To Find</u>:

The Area of Shaded region

<u>Solution:</u>

When the dimensions of parallelogram and the dimensions of rectangle are given, we need to find the Shaded region using this formula:

\boxed{\tt \longrightarrow Area  = (Parallelogram  - Rectangle)}

We know that the formula of Parallelogram is base*height[b×h] and the formula of rectangle is length*breadth[l*b] .

\tt\longrightarrow \: Area =B×h-l×b

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<u>Simplify it.</u>

<em>[</em><em>Follow BODMAS Rule strictly while </em><em>simplifying]</em>

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\rule{225pt}{2pt}

I hope this helps!

8 0
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