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Answer:
Percent of error of Logan's Estimate is 12.5%
Step-by-step explanation:
Given:
Actual Volume of sample =48 mL
Estimated Volume of sample = 42 mL
We need to find the percent errors of Logan estimate.
To calculate percent of error below are the steps.
Step 1: Subtract the Actual value from the estimated value.
Step 2: Take the absolute value of step 1
Step 3: Divide that answer by the Actual value.
Step 4: Multiply that answer by 100 and add the % symbol to express the answer as a percentage.
Now Substituting the values we get;
Step 1: To Subtract Actual Volume with Estimated Volume
Estimated Volume of sample - Actual Volume of sample = 42 - 48 = -6 mL
Step 2: Find Absolute value we get;
Step 3 : Divide that answer by the Actual volume.
Step 4: Multiply that answer by 100 and add the % symbol to express the answer as a percentage.
Hence Percent of error of Logan's Estimate is 12.5%
We know the following:
Cylinder volume: V₁ = π r² h
Ball (sphere) volume:V₂ =
π r³
where:
V - volume
r - radius of base of cylinder and diameter of ball
h - height of cylinder.
R = 13 cm ⇒ r = 13 ÷ 2 = 6.5
π = 3.14
a) Since balls touch all sides of cylinder (as shown in image), it can be concluded that height of cylinder is equal to sum of diameters of 3 balls and that radius of base of cylinder is equal to radius of ball:
h = 3 × r = 3 × 13 cm = 39 cm
r = 6.5 cm
So,
V₁ = <span>π r² h
</span><span>V₁ = </span>3.14 × (6.5 cm)² × 39 cm
V₁ = 5,173.9 cm³
b. The total volume of three balls is the sum of volumes of each ball:
Vₐ = 3 × <span>V₂
</span>Vₐ = 3 × <span> π r³
</span>Vₐ = 3 × 3.14<span> (6.5 cm)³</span>
Vₐ = 3,449.3 cm³
c. Percentage of the volume of the container occupied by three balls ould be expressed as ratio of volume of three balls and volume of cylinder:
V =
×100
V =
×100
V = 0.6666 ×100
V = 66.66%
Cylinder volume: V₁ = π r² h
Ball (sphere) volume:V₂ =
where:
V - volume
r - radius of base of cylinder and diameter of ball
h - height of cylinder.
R = 13 cm ⇒ r = 13 ÷ 2 = 6.5
π = 3.14
a) Since balls touch all sides of cylinder (as shown in image), it can be concluded that height of cylinder is equal to sum of diameters of 3 balls and that radius of base of cylinder is equal to radius of ball:
h = 3 × r = 3 × 13 cm = 39 cm
r = 6.5 cm
So,
V₁ = <span>π r² h
</span><span>V₁ = </span>3.14 × (6.5 cm)² × 39 cm
V₁ = 5,173.9 cm³
b. The total volume of three balls is the sum of volumes of each ball:
Vₐ = 3 × <span>V₂
</span>Vₐ = 3 × <span>
</span>Vₐ = 3 ×
Vₐ = 3,449.3 cm³
c. Percentage of the volume of the container occupied by three balls ould be expressed as ratio of volume of three balls and volume of cylinder:
V =
V =
V = 0.6666 ×100
V = 66.66%