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lubasha [3.4K]
3 years ago
12

Which point has the coordinates (-2.5, 5.5)?

Mathematics
2 answers:
Kryger [21]3 years ago
8 0
If i’m not mistaken, point G so answer C.
serious [3.7K]3 years ago
7 0
It is point G. Answer is C
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Identify two composite numbers that each have 8 as factor
Kay [80]

There is an infinite list of such numbers.
A few of them are ...

8
40
64
72
6,336
100 thousand
1million
8 million


5 0
3 years ago
Read 2 more answers
Are these two expressions equivalent?<br> 6 + 3 and 3 + 6
labwork [276]

Answer: Yes its equivalent

Step-by-step explanation:

6 + 3 =9 and 3 + 6= 9

9 = 9

You should know this smh

6 0
3 years ago
Pls I need it asap it's due in 5 minutes. with steps pls​
Reptile [31]

Answer:

Solution → (2, -1)

Step-by-step explanation:

Input-output values table for equation (1),

2x + y = 3

x          -1          0         1         2          

y          5          3         1         -1

Input-output values table for equation (2),

y = x - 3

x         -1          0         1         2  

y         -4        -3        -2        -1

Now plot these points to get the graphs of both the equations.

Common point (2, -1) of both the lines will be the solution of the system of equations.

5 0
3 years ago
What are the coordinates of the midpoint of the line segment with endpoints (2, -5) and (8, 3)
rewona [7]

Answer: (5,-1)

Step-by-step explanation:

5 0
3 years ago
5x - y + z = -6<br> 2x + 7y + 3z = 8<br> x + 2z = 6
BabaBlast [244]

Answer:

Step-by-step explanation:

The system of equations given are:

 

 5x - y + z = -6   ------------- i

 2x + 7y + 3z = 8  ---------- ii

  x + 2z = 6 ----------------- iii

Let us deal with equation i and ii first since they have 3 variables x, y and z;

      5x - y + z = -6                 x 7

       2x + 7y + 3z = 8            x 1

    35x  - 7y + 7z  = -42   ----  iv

      2x  + 7y + 3z  = 8       ---- v

Add equation iv and v;

    37x + 10z  = -34 ------vi

So, let us solve equation vi and iii:

               x + 2z = 6 - ---------- iii   x 10

               37x + 10z  = -34  --- iv  x 2

    10x + 20z   = 60         vi

     74x + 20z  = -68        vii

Subtract vi  - vii;

      -64x  = 128

          x  = -2

So;    put x  = -2 into iii;

           x + 2z  = 6

           -2 + 2z  = 6

            2z  = 6 + 2  = 8

           z  = 4

Put x  = -2 and z = 4 into equation i;

  5(-2) - y + 4  =  - 6

   -10 -y  +4  = -6

       -6  - y  = -6

             -y  = 0

              y  = 0

5 0
3 years ago
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