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Lubov Fominskaja [6]
3 years ago
9

Kelsey buys 4 packages of juice boxes for a class party. Each pack has 1 point 5 rows with 2 juice boxes in each row. How many b

oxes of juice does Kelsey buy in all?​
Mathematics
1 answer:
vfiekz [6]3 years ago
4 0

Answer:

She bought a total of 12 juice boxes

Step-by-step explanation:

Here, we want to calculate the number of juice boxes bought by Kelsey.

Total package bought = 4

Each pack has 1.5 rows, so the total number of rows = 1.5 * 4 = 6 rows

There are 2 boxes per row, so the number of juice boxes will be 2 * 6 = 12 boxes

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The first two pieces are the same, let each of those equal x, so you have x + x = 2x

The 3rd piece is the sum of the first two + 4, so this would be 2x + 4

Now you have 2x + 2x + 4 = 100 cm

Combine like terms:

4x +4 = 100

Subtract 4 from both sides

4x = 96

Divide both sides by 4

X = 24

First piece is 24 cm

Second piece is 24 cm

Third piece is 52 cm

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A beverage company surveyed 450 adults to determine the demand for summer drinks.
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Answer:

B

Step-by-step explanation:

total number of people minus people who prefer soda, iced tea, or lemonade= people who prefer water

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Prove the equation (2x+5)2 = 4x (x + 5) +25
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Answer:  x = -5/2 and x = -3/2

Step-by-step explanation:

(2x + 5)2 = 4x (x + 5) +25

   4x + 10 = 4x² + 20x + 25

   [minus 4x on both sides.]

            10 = 4x² + 16x + 25

   [minus 10 on both sides.]

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ac = 4(15) = 60,then find the factors that add up to 16, which is 6 and 10.

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An investment of $8,000 earns interest at an annual rate of 7% compounded continuously. Complete parts (A) and (B) below. Click
Sergeeva-Olga [200]

Answer:

A.    \mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}

B.    \mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }

Step-by-step explanation:

Given that:

An investment of  Amount = $8000

earns  at an annual rate of interest = 7% = 0.07 compounded continuously

The objective is to :

A)  Find the instantaneous rate of change of the amount in the account after 2 year(s).

we all know that:

A = Pe^{rt}

where;

A = (8000) \ e ^{0.7t}

The instantaneous rate of change = \dfrac{dA}{dt}

\dfrac{dA}{dt} = \dfrac{d}{dt}(8000 \ e ^{0.07t} )

= 8000 \dfrac{d}{dt}e^{0.07 \ t}

\dfrac{dA}{dt}= 8000 (0.07)e^{0.07 \ t}

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At t = 2 years; the instantaneous rate of change is:

\dfrac{dA}{dt}|_{t=2}= 560 e^{0.07 \times 2}

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(B) Find the instantaneous rate of change of the amount in the account at the time the amount is equal to $12,000.

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\dfrac{12000 }{8000}= e^{0.07 \ t}

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t = 0.405465 /0.07

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At t = 5.79

\dfrac{dA}{dt}|_{t = 5.79}= 560 e^{0.07 \times 5.79}

\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }

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