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faust18 [17]
2 years ago
6

Find the slope of the line that passes through the given points

Mathematics
1 answer:
7nadin3 [17]2 years ago
4 0

The slope should be m= -9/11

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Write an equation in slope-intercept form that has m = 5/4 through (-4,-3)
timama [110]

Answer:

y=5/4x + 2

Step-by-step explanation:

Ok so in the point (-4,-3) -4 is x and -3 is y. Now, since you have the slope, 5/4, you can put it into an equation. -3= 5/4(-4) + b. When you multiply 5/4 x -4 you get -3=-5 + b so then add 5 to both sides to get rid of it and you have 2=b. And your equation would be y=5/4x + 2

4 0
3 years ago
On december 1, jonas jewelry wholesale center started with an inventory of 1,000 watches. shipments of 168, 231, and 411 were se
denis-greek [22]

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

Total watches in an inventory = 1000

Number of shipments sent out = 168, 231, 411

So, Remaining inventory of watches would be :

1000-(168+231+411)\\\\=1000-810\\\\=190

New receipts = 21, 145 and 11

So, Number of watches on hand becomes :

190+(21+145+11)\\\\=367

Hence, Third option is correct.

5 0
3 years ago
PLEASE HELP ILL MAKE YOU BRAINLIEST!!!!<br><br>What is the length of line segment MQ?
Salsk061 [2.6K]
The length is 11 units. x3
7 0
3 years ago
Read 2 more answers
2x + 3 + 4x + 8 = 3x - 10
vodomira [7]

\text {Hello! Let's solve this Equation!}

\text {Your First Step is to Simplify the Equation:}

\text {(2x+4x)+(8+3)}

\text {6x+11=3x-10}

\text {The Next Step is to Subtract 3x:}

\text {6x+11-3x=3x-10-3x}\\\text {3x+11=-10}

\text {Next Step is to Subtract 11:}

\text {Q: Why Subtract 11?}

\text {A: So they cancel out. We cross them out once we subtract.}

\text {3x+11-11=-10-11}\\\text {3x=-21}

\text {The Final Step is to Divide 3:}

\text {3x/3=-21/3}

\text {Your Answer will be}

\fbox {x=-7}

\text {Best of Luck!}

\text {-LimitedX}

8 0
3 years ago
At noon, Bradley began steadily increasing the
barxatty [35]

Answer:

25.5 mph

Step-by-step explanation:

So Bradley's speed can be modeled by the equation y=2x+40 where y=speed, x=time in hours after noon, and b=initial speed

So 12:15 is 15 minutes after noon, which is also 0.25 or 1/4 of an hour after noon. This is the x-value. Plug this into the equation to get his speed at 12:15

y=2(0.25)+40

y=0.5+40

y=40.5

So his speed was 40.5 at the time and since he was going 15 miles over the speed limit, the speed limit is 15 less than his speed

40.5 - 15 = 25.5

8 0
2 years ago
Read 2 more answers
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