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Katarina [22]
3 years ago
13

A square measures 8 inches on each side. What is its area rounded off to the nearest square centimeter? (Note: 1 inch ≈ 2.54 cm)

a) 413 sq cm b) 512 in.² c) 64 cm² d) 32 in.²
Mathematics
2 answers:
pickupchik [31]3 years ago
7 0

Answer:

C.) 413 cm^2

Step-by-step explanation:

To figure out the area of a square, much like a rectangle we multiply length × width.  In this case because the length and width are the same (definition of a square) then it's simply s^2 and 8 inches is 20.32 cm (8x2.54):

s^2=20.32^2=412.90 \approx 413

a.) 413 cm^2

adoni [48]3 years ago
5 0

Answer:

41 sq cm is the answer

Step-by-step explanation:

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The sphere is _____ cubic centimeters bigger than the cube. (Round to the nearest cubic centimeter.)
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The sphere is 10762 cubic centimeters bigger than the cube.

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We want to find the difference in the volumes of the sphere and the cube.

To do this, we have to find the volumes of the sphere and cube and subtract that of the cube from the sphere.

The volume of a sphere is given as:

V=\frac{4}{3}\pi r^3

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The radius of the sphere is 15 centimeters. Therefore, the volume of the sphere is:

\begin{gathered} V=\frac{4}{3}\cdot\pi\cdot15^3 \\ V\approx14137\operatorname{cm}^3 \end{gathered}

The volume of a cube is given as:

V=s^3

where s = length of the side

The length of the side of the cube is 15 centimeters. Therefore, the volume of the cube is:

\begin{gathered} V=15^3 \\ V=3375\operatorname{cm}^3 \end{gathered}

Therefore, the difference in the volumes of the sphere and cube is:

\begin{gathered} V_d=V_s-V_c \\ V_d=14137-3375 \\ V_d=10762\operatorname{cm}^3 \end{gathered}

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