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jarptica [38.1K]
3 years ago
6

The length of one rectangle is 4 and the width is 2x-6. The length of another rectangle is 1/2 and the width is 6x+2. How much l

arger is the area of the first rectangle than the area of the second rectangle.
Mathematics
1 answer:
Assoli18 [71]3 years ago
8 0
The answer is that the first one is not the longer one the second one is.
the first one equals 2
the second one equals 5
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The length of a rectangular field is 6 metres longer than its width. If the area of the field is 72 square metres, What are the
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Answer:

Let's call the length of the field "l", and the width of the field "w".

If the area of the field is 72 square meters, then we have:

l x w = 72

And if the length is 6 meters longer than the width, we have:

l = w+6

So looking at the first equation (l x w = 72), we can substitute the l for a w+6.

And we obtain:

(w+6) x (w) = 72

Which simplifies to w^2 + 6w = 72.

This quadratic equation is pretty easy to solve, you just need to factor it.

w^2 + 6w - 72 = 0

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This leaves the roots of the  quadratic equation to be 6 and -12, but in this case, a width of -12 wouldn't make sense.

So, the width of the rectangular field is 6, and the length of the field is 12.

Let me know if this helps!

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frutty [35]
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Find all the zeros of f(x) = 2x - 5x² - 4x + 10.
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antiseptic1488 [7]

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6 0
3 years ago
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What is the volume of a cylinder, in cubic m, with a height of 5m and a base diameter of 20m? Round to the nearest tenths place
makvit [3.9K]

Answer: Volume of the cylinder = 1570 m³

Step-by-step explanation:

The formula for determining the volume of a cylinder is expressed as

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π is a constant whose value is 3.14

From the information given,

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Radius = 10 m

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Volume = 1570 m³ rounded to the nearest tenth

8 0
3 years ago
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