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jarptica [38.1K]
2 years ago
6

The length of one rectangle is 4 and the width is 2x-6. The length of another rectangle is 1/2 and the width is 6x+2. How much l

arger is the area of the first rectangle than the area of the second rectangle.
Mathematics
1 answer:
Assoli18 [71]2 years ago
8 0
The answer is that the first one is not the longer one the second one is.
the first one equals 2
the second one equals 5
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Let z= -5 sqrt 3/2 + 5/2i and w=1 + sqrt 3i
MrRissso [65]

a.

z=-\dfrac{5\sqrt3}2+\dfrac52i=5\left(-\dfrac{\sqrt3}2+\dfrac12i\right)=5e^{i5\pi/6}

w=1+\sqrt3\,i=2\left(\dfrac12+\dfrac{\sqrt3}2i\right)=2e^{i\pi/3}

b. Not exactly sure how DeMoivre's theorem is relevant, since it has to do with taking powers of complex numbers... At any rate, multiplying z and w is as simple as multiplying the moduli and adding the arguments:

zw=5\cdot2e^{i(5\pi/6+\pi/3)}=10e^{i7\pi/6}

c. Similar to (b), except now you divide the moduli and subtract the arguments:

\dfrac zw=\dfrac52e^{i(5\pi/6-\pi/3)}=\dfrac52e^{i\pi/2}

8 0
3 years ago
I need help with this question
alex41 [277]
Since the triangle is cut in half, I’m guessing it’s 22.5
7 0
3 years ago
Who does gyro never never ever bet on even numbers math worksheet!!
uranmaximum [27]
I really do not know the answer to this question
6 0
3 years ago
Ln how many ways 5 person sitted in a round table having 8 seats?
kvasek [131]

Answer: First consider the case that ‘just’ 5 persons are seated around a round table.

Clearly, ‘just’ 5 persons can be seated around a round table in (5 - 1)! = 4! = 24 ways.

Now, one vacant chair is to be inserted among them.

Say, for a particular sitting arrangement ‘ABCDE’; there are 5 scopes available for inserting the vacant chair - between A and B, between B and C, between C and D, between D and E & between E and A.

So, there are 5*24 = 120 ways available that 5 persons can sit around a round table with 6 chairs.

Step-by-step explanation:

First consider the case that ‘just’ 5 persons are seated around a round table.

Clearly, ‘just’ 5 persons can be seated around a round table in (5 - 1)! = 4! = 24 ways.

Now, one vacant chair is to be inserted among them.

Say, for a particular sitting arrangement ‘ABCDE’; there are 5 scopes available for inserting the vacant chair - between A and B, between B and C, between C and D, between D and E & between E and A.

So, there are 5*24 = 120 ways available that 5 persons can sit around a round table with 6 chairs.

5 0
3 years ago
3. Sadie and Josie are asked to wrie an expression equivalent to 3(2x+3y).
Andrews [41]
The answer is A!
Sadie is correct because 3(2x+3y) equals 6x+9y
5 0
2 years ago
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