Lets try to solve this problem using 2 equations, also,we will have bananas=b and pears =p
5b+3p= $3.80
2b+4p= $3.20 i will divide this equation by 2 and get
b+2p= $ 1.60 we subtract 2p from both side so i can find the cost for 1 banana
b+2p-2p=1.60-2p
b= $1.60-2p
I will replace the b in the first equation now,
5(1.60-2p)+3p=$3.80
8-10p+3p=3.80 solving for p
8-7p=3.80 we subtract 8 from both sides
-7p=-8+3.80
-7p=-4.20 we multiply both sides by (-1)
7p=4.20 we divide now both sides by 7
p=0.60 a pear cost 0.60 cents
a banana is b=1.60-2p, b=0.40 cents
If two lines intersect, then there is only one solution - where they cross.
Looking at the graph, we can see the intersection point of these two lines.
The intersection point is (1,1) - one unit to the right of the origin and one unit up.
Hope this helps! :)
-7(z - 6) = -70
-7z + 42 = -70
- 42 -42
-7z = -112
-7z/-7 = -112/-7
z = 16
Answer: z = 16
Answer:
901$
Step-by-step explanation:
Answer: 10
Step-by-step explanation:
20/2=10
pairs of two
