What is The Kissing Number Problem?

the monthly rent for an 800 square foot office is $975. For an 1100 square foot office, the rent is $1125. Write and solve a lin

IgorC [24]

For 300 more square feet the rent is $150 more.
Rent per additional square foot is 150/300 or 0.50.
For an additional 400 square feet the rent is an additional 400(0.50) or $200.
The rent for 1500 feet squared office is $1325.

6 0

3 years ago

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Assume that we have two events, and , that are mutually exclusive. Assume further that we know and . If an amount is zero, enter

sweet [91]

Answer:

Explained below.

Step-by-step explanation:

The complete question is:

Assume that we have two events, A and B, that are mutually exclusive. Assume further that we know P(A) = 0.30 and P(B) =0.40.

What is P(A and B)?

What is P(A | B)?

Is P(A | B) equal to P(A)?

Are events A and B dependent or independent?

A student in statistics argues that the concepts of mutually exclusive events and independent events are really the same, and that if events are mutually exclusive they must be independent. Is this statement accurate?

What general conclusion would you make about mutually exclusive and independent events given the results of this problem?

Solution:

The probability of the two events A and B are:

P(A) = 0.30 and P(B) =0.40

(a)

Compute the value of P (A ∩ B) as follows:

$P(A\cap B)=0$

This is because mutually exclusive events are those events that cannot occur together.

(b)

Compute the value of P (A | B) as follows:

$P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{0}{0.40}=0$

Thus, the value of P (A | B) is 0.

(c)

No, P (A | B) is not equal to the P (A).

(d)

As mentioned in part (a), mutually exclusive events are those events which cannot occur together.

That is, $P(A\cap B)=0$ .

Events A and B are independent if the chance of their concurrent happening is equivalent to the multiplication of their distinct probabilities.

That is, $P(A\cap B)=P(A)\times P(B)$ .

The concepts of mutually exclusive events and independent events are not the same.

(e)

As the it is provided that A and B are mutually exclusive events, we know that $P(A\cap B)=0$ .

Now compute the value of $P(A)\times P(B)$ as follows:

$P(A)\times P(B)=0.30\times 0.40=0.12\neq 0$

Thus, the events A and B are not independent.

Thus, if two events are mutually exclusive events they cannot be independent.

4 0

3 years ago

If x,y and z are positive integers and 3x=4y=7z,

Pani-rosa [81]

3x=4y=7z
so
GCF:
3 * 4 * 7 = 84

3x = 84
x = 28

4y = 84
y = 21

7z = 84
z = 12

least possible value for
x + y + z = 28 + 21 + 12 = 61

answer
(d) 61

5 0

3 years ago

Prove that the statement (ab)^n=a^n * b^n is true using mathematical induction.

mamaluj [8]

Answer:

see below

Step-by-step explanation:

(ab)^n=a^n * b^n

We need to show that it is true for n=1

assuming that it is true for n = k;

(ab)^n=a^n * b^n

( ab) ^1 = a^1 * b^1

ab = a * b

ab = ab

Then we need to show that it is true for n = ( k+1)

or (ab)^(k+1)=a^( k+1) * b^( k+1)

Starting with

(ab)^k=a^k * b^k given

Multiply each side by ab

ab * (ab)^k= ab *a^k * b^k

( ab) ^ ( k+1) = a^ ( k+1) b^ (k+1)

Therefore, the rule is true for every natural number n

5 0

3 years ago

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Figure ABCDE is similar to figure FGHIJ. What is the length of segment FG?

Viefleur [7K]

It must be 6 since the length sides r doubled and it's similar

7 0

3 years ago

What is The Kissing Number Problem?​

What is The Kissing Number Problem?