Well it depends on how many tables you are using and if all the sides of the table are equal lengths....you can it will not hurt anything just make sure you right down all of the area length/width that you cover that way you get the amount you need :) remember to hit that thanks button please:)
Yo sup??
cosx>0 in the 1st and 4th quadrant.
tanx>0 in the 1st and 3rd quadrant.
therefore the common solution is x lies in 1st quadrant.
Hence the correct answer is option A.
Hope this helps
Given that triangle m and n are similar, then the implication is the ratio of the corresponding sides are the same and the corresponding angles are equal. This implies that if the two angles of triangle m measure 32° and 93°, then the possible size for the two angles in triangle n will be 32° and 93°.
Answer:
we are looking for F
but in the question it stated that f(n) and at the end it also stated that f(1) so n=1
Step-by-step explanation:
we are using BODMAS
f(n-1)+1
f(1-1)+1=0+1
f=1
