Someone Plz help ASAP!!!

coldgirl [10]

The answer is D because if you get the same answers from each shape that is congruent

7 0

3 years ago

40% of the students on a field trip love the museum. If there are 20 students on the field trip, how many love the museum?

ss7ja [257]

If there's a total of 20 students and 40% love the museum. 20 * .40 = 8 students love the museum.

5 0

3 years ago

Find the least squares regression equation using the school year (in number of years after 2000) for the input variable and the

Ad libitum [116K]

Answer-

The least squares regression equation using the school year (in number of years after 2000) for the input variable and the average cost (in thousands of dollars) for the output variable is "y=0.937x+12.765" .

Solution-

The independent variable / input variable= x = Number of years after 2000 ( = year-2000)

The dependent variable / output variable = y = Average cost in thousands of dollars

(The table has been attached herewith.)

To find the regression equation for a group of (x,y) points,

We have to calculate the slope and y-intercept, then we can put those values in the equation y = mx + c ( Slope - Intercept formula)

We know that,

$Slope=m=\frac{N\sum xy -\sum x\sum y}{N\sum x^{2}- (\sum x)^{2}}$

Putting the values from the table,

$m=\frac{(8 \times 1020.206)-(52 \times 150.894)}{(8 \times 3810)-(52^2)}$

( ∵ Instead of 150,894 we have to put 150.894 as we have find the line for year and thousands of dollars )

$\Rightarrow m =\frac{8161.648-7846.488}{3040-2704} =\frac{315.16}{336}=0.937$

Now, for the y-intercept,

$c =\frac{\sum y -m(\sum x)}{N}$

Putting the values,

$c=\frac{150.894-(52 \times 0.937)}{8}=\frac{102.125}{8}=12.765$

Now, putting the values of c and m, in the Slope-Intercept formula,

$y=0.937x+12.765$

3 0

3 years ago

A study was conducted looking at the association between the number of polyps in the colon and mean grams of fiber consumed per

rewona [7]

Answer:

C) The Spearman correlation results should be reported because at least one of the variables does not meet the distribution assumption required to use Pearson correlation.

Explanation:

The following multiple choice responses are provided to complete the question:

A) The Pearson correlation results should be reported because it shows a stronger correlation with a smaller p-value (more significant).

B) The Pearson correlation results should be reported because the two variables are normally distributed.

C) The Spearman correlation results should be reported because at least one of the variables does not meet the distribution assumption required to use Pearson correlation.

D) The Spearman correlation results should be reported because the p-value is closer to 0.0556.

Further Explanation:

A count variable is discrete because it consists of non-negative integers. The number of polyps variable is therefore a count variable and will most likely not be normally distributed. Normality of variables is one of the assumptions required to use Pearson correlation, however, Spearman's correlation does not rest upon an assumption of normality. Therefore, the Spearman correlation would be more appropriate to report because at least one of the variables does not meet the distribution assumption required to use Pearson correlation.

8 0

3 years ago

Complete the inequality statement. 4 1/4___ 17/4

Mumz [18]

Answer:

they are =

im sorry it was a little late

8 0

3 years ago