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zaharov [31]
4 years ago
8

Someone Plz help ASAP!!!

Mathematics
1 answer:
Butoxors [25]4 years ago
6 0

Answer:

c=3/16

n=4/3

Step-by-step explanation:

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IM SOOOO STUCKKKK HELLPPPPPPPPPPP!!
KonstantinChe [14]

Answer:

18

Step-by-step explanation:

x² = 16² + 30² - 2(16)(30)cos 30°

x² = 256 + 900 - 960(0.866)

x² = 1156 - 831.36

x² = 324.64

x = 18.02

Approx. 18

Please mark my answer as brainliest

3 0
3 years ago
Read 2 more answers
Negative 3 over 4 t equals 5
tatuchka [14]

Answer:

5645

Step-by-step explanation:

hsususikzz577sss8d0d8x s9s72383 333rd St. east St. Louis 83inches 2is 2273

4 0
3 years ago
How do you do this equation
RUDIKE [14]
When you solve, a quadratic formula is set up as ax^2+bx+c so in this scenario a is 1, b is -1 and c is -6.
-(-1)+- √- 1^2-4(1)(-1)/2(1) is
1+/-√1+4/2 equals -2 and 3 making the answer c
4 0
3 years ago
How many solutions can be found for the system of linear equations represented on the graph?
Anon25 [30]

Answer:

No Solution

Step-by-step explanation:

As the two lines have the identical slope (-1/2x), that means these two lines are parallel, and therefore they have no solution.

3 0
3 years ago
At a high school, students can choose between three art electives, four history electives, and five computer electives. Each stu
V125BC [204]

Answer:

\frac{^3C_1\times ^4C_1}{^{12}C_2}

Step-by-step explanation:

Given,

Art electives = 3,

History electives = 4,

Computer electives = 5,

Total number of electives = 3 + 4 + 5 = 12,

Since, if a student chooses an art elective and a history elective,

So, the total combination of choosing an art elective and a history elective = ^3C_1\times ^4C_1

Also, the total combination of choosing any 2 subjects out of 12 subjects = ^{12}C_2

Hence, the probability that a student chooses an art elective and a history elective = \frac{\text{Total combination of choosing an art elective and a history}}{\text{ Total combination of choosing any 2 subjects}}

=\frac{^3C_1\times ^4C_1}{^{12}C_2}

Which is the required expression.

3 0
3 years ago
Read 2 more answers
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