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inessss [21]
3 years ago
12

An artist is cutting pieces of ribbon to use in a project. Each piece he cuts measures

Mathematics
1 answer:
skad [1K]3 years ago
8 0

Answer:

the artist cuts off 10 inches of ribbon in total

Step-by-step explanation:

2.5 × 4 = 10

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Please help meeeeeeeeeee
kherson [118]

Answer:

4/8 or

1/2

Step-by-step explanation:

if there are 8 students and 4 of them study Chemistry then we take those 4 out of the equation then there are 4 left and there are now 4 possibly choses

5 0
3 years ago
I need help in solving this problem (ASAP)
zhannawk [14.2K]

Answer:

The answer is y=24

Step-by-step explanation:

The <u>triangle is a 30-60-90 triangle</u>, which means that the it follows the <em>respective ratio of x:x</em>\sqrt{3}<em>:2x. </em>Since we know that the 30 degree value is 8\sqrt{3}, we can establish that the 60 degree value is 8\sqrt{3}*\sqrt{3} = 24.

4 0
3 years ago
Help me Please!! Math is a struggle tbh
grandymaker [24]

Answer:

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A particle moves along the x-axis so that at any time t, t ≥ 0, its acceleration is a(t) = -4sin(2t). If the velocity of the par
sasho [114]

The velocity of the particle is given by

v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du

Since a(t)=-4\sin2t and v(0)=7, we get

\displaystyle\int_0^ta(u)\,\mathrm du=\int_0^t-4\sin2u\,\mathrm du=2\cos2u\bigg|_0^t=2\cos2t-2

\implies v(t)=2\cos2t+5

Similarly, the position function is obtained via

x(t)=x(0)+\displaystyle\int_0^tv(u)\,\mathrm du

We know v(t) and we're told that x(0)=0, so

\displaystyle\int_0^tv(u)\,\mathrm du=\int_0^t(2\cos2u+5)\,\mathrm du=\sin2u+5u\bigg|_0^t=\sin2t+5t

\implies x(t)=\sin2t+5t

making the answer A.

3 0
3 years ago
One positive integer is 5 times another positive integer and their product is 320. What are the positive integers?​
seropon [69]

Answer:

The integers are (x, y) = (40, 8).

Step-by-step explanation:

x = 5y

xy = 320

Substitute the first equation into the second equation.

(5y)(y) = 320

5y^2 = 320

y^2 = 64

y = 8 (y must be positive)

The integers are (x, y) = (40, 8).

6 0
3 years ago
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