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harina [27]
3 years ago
5

Factor the binomial or identify it as prime.

Mathematics
2 answers:
Makovka662 [10]3 years ago
7 0
The answer to this problem is A
:)
In-s [12.5K]3 years ago
5 0

Answer:

The correct answer is B,

Step-by-step explanation:

Since the higher value of z's power, is 4, an even number, and the second number is negative, we can think that this binomial is made of a difference of squares, so that is what we are going to factorize.

First, extract the common number (if any), the number 2, we have now>

2*(z^{4}-1)

This is convenient since "1" is a wonderful number that has this feature>1^{n}= 1 No matters what n's value is,

so the first equation 2*(z^{4}-1) can be written as (2*(z^{4}-1)=2*((z^{2})^{2}-1^{2})=2*(z^{2}-1)*(z^{2}+1)

The later termn, can also be factorized, using the same as befre.

(z^{2}-1)=(z-1)*(z+1)

Remember that z^{4}=(z^{2})^{2}

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Step-by-step explanation:

If a boy student was picked, the probability that they passed is 0.25 * 0.4 = 0.1.

If a girl student was picked, the probability that they passed is 0.75 * 0.25 = 0.1875.

Total probability = (0.1 + 0.1875) * 100% = 28.75%.

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Laney bought some candy from the bulk food store. She bought a 290 gram bag of gummy worms, a 450 gram bag of sour keys, and 670
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A

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The rectangular prism is to be sliced perpendicular to the shaded face is to pass through point A,perpendicular to the front fac
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Answer:

<h2>C: 3 inches by 6 inches</h2>

Step-by-step explanation:

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The scores on the GMAT entrance exam at an MBA program in the Central Valley of California are normally distributed with a mean
Kaylis [27]

Answer:

58.32% probability that a randomly selected application will report a GMAT score of less than 600

93.51%  probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 591, \sigma = 42

What is the probability that a randomly selected application will report a GMAT score of less than 600?

This is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{600 - 591}{42}

Z = 0.21

Z = 0.21 has a pvalue of 0.5832

58.32% probability that a randomly selected application will report a GMAT score of less than 600

What is the probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600?

Now we have n = 50, s = \frac{42}{\sqrt{50}} = 5.94

This is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{s}

Z = \frac{600 - 591}{5.94}

Z = 1.515

Z = 1.515 has a pvalue of 0.9351

93.51%  probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

What is the probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600?

Now we have n = 50, s = \frac{42}{\sqrt{100}} = 4.2

Z = \frac{X - \mu}{s}

Z = \frac{600 - 591}{4.2}

Z = 2.14

Z = 2.14 has a pvalue of 0.9838

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

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