Question

Factor the binomial or identify it as prime.

Answer 1

The answer to this problem is A
:)

Answer 2

Answer:

The correct answer is B,

Step-by-step explanation:

Since the higher value of z's power, is 4, an even number, and the second number is negative, we can think that this binomial is made of a difference of squares, so that is what we are going to factorize.

First, extract the common number (if any), the number 2, we have now>

$2*(z^{4}-1)$

This is convenient since "1" is a wonderful number that has this feature>$1^{n}= 1$ No matters what n's value is,

so the first equation $2*(z^{4}-1)$ can be written as $(2*(z^{4}-1)=2*((z^{2})^{2}-1^{2})=2*(z^{2}-1)*(z^{2}+1)$

The later termn, can also be factorized, using the same as befre.

$(z^{2}-1)=(z-1)*(z+1)$

Remember that $z^{4}=(z^{2})^{2}$