Suppose :
2^x = t ..**&**.. 3^y = u
_____________________________
t + u = 9 × 3 3t + 3u = 27
=====》
2t - 3u = 8 2t - 3u = 8
+ __________
5t = 35
5 × t = 5 × 7
t = 7
&
u = 2
________________________________
Thus :
2^x = 7 ===》 x = Log _ 2 { 7 }
3^y = 2 ===》 y = Log _ 3 { 2 }
Answer:
Step-by-step explanation :
Let x be the number.
x × 8/100 =48
x =48 × 100/8
Now cut 48 by 8 and we get 6.
x = 6 ×100
x =600
So 600 is the required number.
Answer:
the answer is 6
Step-by-step explanation:
6×3=18
So 6×5=30, 6×2=12
30-12=18
18=18
