Answer:
3 cars
Step-by-step explanation:
If 12 cars are needed to carry 36 students,
<em>12</em><em>c</em><em>a</em><em>r</em><em>s</em><em> = 36</em>
the number of cars to carry 9 students will be:
xcars = 9
cross the two equations
36x = 12 X 9
36x = 108
x = 108/36
x= 3
Therefore, 3 cars are needed to carry 9 students
OR
12 cars will carry 36 students
so 1 car will carry, (36/12)students
therefore, 1 car will carry 3 students
So, for 9 students,
9students = 9/3 = 3
Answer:
x=Y/2−9/2
Step-by-step explanation:
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Answer:
What do we have to solve for this?
The distance to the top of the building above the range finder can be found from the Pythagorean theorem.
.. d = √(115² -89²) ≈ 72.8 . . . . feet
Adding the height of the range finder, we find the height of the building to be
.. h = d+3 = 75.8 ft
Answer:
We have, 63% × x = 252
or,
63/100 × x = 252
Multiplying both sides by 100 and dividing both sides by 63,
we have

x = 400
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