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3 years ago

8

(02.05)The figure shows three quadrilaterals on a coordinate grid:

2 answers:

erastovalidia [21]3 years ago

7 0

Nd f are similar but not congruent in other words the answer is A!!!

denis-greek [22]3 years ago

5 0

Answer:

A. D and E are similar but not congruent.

Step-by-step explanation:

The side lengths of D are 3 units and 1 unit. The side lengths of E are 2 units and 6 units. The sides are proportional, but are not congruent; this means that the quadrilaterals are similar but not congruent. Choice A is true and choice C is false.

The side lengths of E are 2 units and 6 units. The side lengths of F are 3 units and 1 unit. The sides are proportional, but are not congruent; this means that the quadrilaterals are similar but not congruent. Choice B is false.

The side lengths of D are 3 units and 1 unit. The side lengths of F are 3 units and 1 unit. The sides are congruent; this means that the quadrilaterals are congruent. Choice D is false.

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3 years ago

Val buys a computer for $720. If this is 120% of what the store paid for the

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3 years ago

Xy = –16. What is the constant of variation for this relationship?

olganol [36]

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6 0

3 years ago

Los dueños de un restaurante cultivan sus propios

hammer [34]

Answer:

Quedan 2.083 m^3 de agua en el reservorio.

Equivalen a 2083 litros.

Step-by-step explanation:

Los dueños del restaurante tienen un reservorio de agua cuyo volumen es de 6.25 m^3.

Si han utilizado 2/3 del reservorio, esto implica que aún quedan en el reservorio una tercera parte del volumen original (1/3).

Entonces, la cantidad de metros cúbicos (m^3) de agua que quedan en el reservorio se puede calcular como:

$V=(1/3)\cdot V_0=(1/3)\cdot6.25\,m^3=2.083\,m^3$

Este valor equivale a un volumen en litros de:

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7 0

3 years ago

The compressive strength of concrete is normally distributed with mu = 2500 psi and sigma = 50 psi. A random sample of n = 8 spe

ipn [44]

Answer:

The standard error of the sample mean is _17.677_ psi.

Step-by-step explanation:

<u>Explanation</u>:-

A random sample of n = 8 specimens is collected.

Given sample size is n = 8

Given mean of the population 'μ' = 2500 psi

standard deviation 'σ' = 50 psi

Let x⁻ is the mean of the observed sample

Standard error of the sample mean = $\frac{S.D}{\sqrt{n} }$ ...(i)

Given Population of standard error (S.D) 'σ' = 50 psi

Now substitute all values in (i)

$S.E = \frac{50}{\sqrt{8} } =17.677$

<u>Conclusion</u>:-

The standard error of the sample mean is _17.677psi.

7 0

3 years ago