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UkoKoshka [18]
3 years ago
5

Susan will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $70 and costs an ad

ditional $0.40 per mile driven. The second plan has no initial fee but costs $0.60 per mile driven. How many miles would Susan need to drive for the two plans to cost the same?
Mathematics
1 answer:
swat323 years ago
4 0

Answer:

350 miles

Step-by-step explanation:

Let x represent the miles driven

The cost with the first plan will be represented by 0.40x + 70

The second plan will be represented by 0.60x

Set these 2 expressions equal to each other and solve for x:

0.40x + 70 = 0.60x

70 = 0.20x

350 = x

So, Susan will have to drive 350 miles for the cost to be the same

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aleksley [76]
3/4 x 12 = 9 in decimal form.
3/4 x 12 = 9/1 in fraction form
6 0
3 years ago
Read 2 more answers
The shape of the distribution of the time required to get an oil change at a 20 minute oil change facility. However, records ind
Katyanochek1 [597]

Answer:

For a mean oil change time of 20.51 minutes there would be a​ 10% chance of being at or​ below

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 21.3, \sigma = 3.9, n = 40, s = \frac{3.9}{\sqrt{40}} = 0.6166

Treating this as a random​ sample, at what mean​ oil-change time would there be a​ 10% chance of being at or​ below?

This is the 10th percentile, which is X when Z has a pvalue of 0.1. So it is X when Z = -1.28.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

-1.28 = \frac{X - 21.3}{0.6166}

X - 21.3 = -1.28*0.6166

X = 20.51

For a mean oil change time of 20.51 minutes there would be a​ 10% chance of being at or​ below

6 0
3 years ago
Miss E. ordered a quilt from an online store .
Firlakuza [10]
I don’t know the first answer but the second one I know. 2.) It should cost her $400 dollars for a quilt that uses 4000 yards of yarn. Tell me if I’m wrong.
3 0
2 years ago
It Says Minute At The End
Kisachek [45]

Answer:

1.368

Step-by-step explanation: 1.14x1.2=1.368

4 0
3 years ago
URGENT!! GIVING BRAINLIEST, 30 POINTS
Yakvenalex [24]

Answer:

No her calculations do not make sense because the area of the smaller walls together is 234 and not 244 the total square feet of the windows and doors are also wrong. She should also subtract the doors and windows from the total so she doesn't over spend on paint. Her answer is correct just the way of finding it is wrong.

Step-by-step explanation:

Walls total sqft: (2(13ft)(9ft))+(2(16ft)(9ft))=234ft²+288ft²=522ft²

Doors+Windows total sqft: ((2(20ft)+(2(15ft))=60ft²+30ft²=90ft²

Total amount of paint needed: 522ft²-90ft²=432ft²

Amount of gallons needed remains the same

Hopefully this makes sense.

8 0
3 years ago
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