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cupoosta [38]
3 years ago
6

What does 7 3/4 - 1 2/7 - 3/2 equal?

Mathematics
1 answer:
Brrunno [24]3 years ago
8 0
I hope this helps you

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How i can answer this question, NO LINKS, if you answer correctly i will give u brainliest!
Helga [31]

Answer:

4:6 = 2:3, the answer is C

Step-by-step explanation:

they visited 4 museums as displayed on the bar and 6 beaches also presented on the bar, which would mean 4:6 and would simplify to 2:3

4 0
2 years ago
During a softball game, Sara threw 70 pitches. Of those pitches, 29 were strikes. What portion of the pitches that Sara threw we
EleoNora [17]
Answer: 0.414


29/70=0.41428571
The thousands place is the third place.
5 0
3 years ago
10. Melissa has $20 to buy bagels and juice for her class. box of bagels bottle of juice 56.13, including tax $2.08, including t
adelina 88 [10]

The inequality for the maximum number of bottles of juice she can buy

6.13+ 2.08b <20.00

Option B

Given

Melissa has $20 to buy bagels and juice for her class

Box of bagels :   6.13 including tax

Bottle of juice: 2.08 including tax

She will buy only one box of bagels that is for 6.13

Let 'b' be the number of bottles of juice she can buy

Total cost should be less than 20 dollars

6.13(one bagels) +2.08(bottles of juices)<20

So the inequality becomes

6.13+2.08b

Learn more :  brainly.com/question/1836165

4 0
2 years ago
Naomi is a sales person. She sold a calculator for $86 and earned 20% commission. How much commission did Naomi earn?
Free_Kalibri [48]

Answer:

$17.20

Step-by-step explanation:

Total commission = cost x percent commission rate

86 x 20 % = 17.20

Total commission = $17.20

3 0
3 years ago
A manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective
Inessa05 [86]

Answer:

(a) P(X \leq 20) = 0.9319

(b) Expected number of defective light bulbs = 15

Step-by-step explanation:

We are given that a manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective independently. A box of 150 bulbs is selected at random.

Firstly, the above situation can be represented through binomial distribution, i.e.;

P(X=r) = \binom{n}{r} p^{r} (1-p)^{2} ;x=0,1,2,3,....

where, n = number of samples taken = 150

            r = number of success

           p = probability of success which in our question is % of bulbs that

                  are defective, i.e. 10%

<em>Now, we can't calculate the required probability using binomial distribution because here n is very large(n > 30), so we will convert this distribution into normal distribution using continuity correction.</em>

So, Let X = No. of defective bulbs in a box

<u>Mean of X</u>, \mu = n \times p = 150 \times 0.10 = 15

<u>Standard deviation of X</u>, \sigma = \sqrt{np(1-p)} = \sqrt{150 \times 0.10 \times (1-0.10)} = 3.7

So, X ~ N(\mu = 15, \sigma^{2} = 3.7^{2})

Now, the z score probability distribution is given by;

                Z = \frac{X-\mu}{\sigma} ~ N(0,1)

(a) Probability that this box will contain at most 20 defective light bulbs is given by = P(X \leq 20) = P(X < 20.5)  ---- using continuity correction

    P(X < 20.5) = P( \frac{X-\mu}{\sigma} < \frac{20.5-15}{3.7} ) = P(Z < 1.49) = 0.9319

(b) Expected number of defective light bulbs found in such boxes, on average is given by = E(X) = n \times p = 150 \times 0.10 = 15.

                                           

5 0
3 years ago
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