3 years ago

A six−sided die, with sides numbered 1,2, 3,4,5, and 6, is tossed. What is the probability of tossing a number less than three?

1 answer:

4 0

$the \ probability= \frac{the \ number \ of \ favorable \ cases}{the \ number \ of \ posibble \ cases} \\ \\ \boxed{p=\frac{2}{6}= \frac{1}{3}}$

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