Answer:
Step-by-step explanation:
From the question we are told that:
Sample size n=9
Number of Green 
Number of yellow 
Number of white 
Probability of Green Followed by yellow P(GY) ball
Generally the equations for when n is even is mathematically given by
Therefore
Generally the equations for when n is odd is mathematically given by
b)
Probability of drawing white ball
Therefore
Therefore
![E(y)=[E(w)-1]\frac{4}{9}](https://tex.z-dn.net/?f=E%28y%29%3D%5BE%28w%29-1%5D%5Cfrac%7B4%7D%7B9%7D)
![E(y)=[\frac{9}{2}-1]\frac{4}{9}](https://tex.z-dn.net/?f=E%28y%29%3D%5B%5Cfrac%7B9%7D%7B2%7D-1%5D%5Cfrac%7B4%7D%7B9%7D)
Answer:
What exactly do you need help with?
Answer:
40, 48, 56
Step-by-step explanation:
8x5 is 40
8x6 is 48
8x7 is 56
I hope this helps have a good day
Given that Erica and AAron,are using lottery system to decide who will wash dishes every night.
They put some red and blue power chips and draw each one. If same colour, Aaron will wash and if not same colours Erica will wash
If the game is to be fair, then both should have equal chances of opportunity for washing.
i.e. Probability for Erica washing = Prob of Aaron washing
i.e. P(different chips) = P(same colour chips)
Say there are m red colours and n blue colours.
Both are drawing at the same time.
Hence Prob (getting same colour) = (mC2+nC2)/(m+n)C2
Probfor different colour = mC1+nC1/(m+n)C2
The two would be equal is mC2 +nC2 = m+n
This is possible if mC2 =m and nC2 = n.
Or m = 2+1 =3 and n =3
That for a fair game we must have both colours to be 3.
