Okay, for this proof, I'll write the steps out.
Statements:
1. ABCD is a parallelogram
2. FG bisects DB
3. <GEB ≡ (pretend congruent symbol) <FED
4. DE ≡ BE
5. <CDA ≡ <ABC
6. < CDB ≡ <DBA
7. triangle DFE ≡ triangle BGE
8. FE ≡ GE
9. DB bisects FG
Reasons:
1. Given
2. Given
3. vertical angles are congruent
4. If bisected, then split into congruent parts
5. opposite angles of a parallelogram are congruent
6. Subtraction Property
7. ASA
8. CPCTC
9. segment split into congruent parts by other segment is bisected.
Hope this helped! :)
2000, since it’s above 1500
Answer:
![\frac{-y-1}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B-y-1%7D%7B8%7D)
Step-by-step explanation:
1/2y - 5/8y = 4/8y - 5/8y = -1/8y
3/4 - 7/8 = 6/8 - 7/8 = -1/8
-1/8y - 1/8 =
-y/8 - 1/8 =
![\frac{-y-1}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B-y-1%7D%7B8%7D)
Answer:
B
Step-by-step explanation:
seeing input/ output boxes= function
y is proportional to some constant (k)(constant of proportionality) times x
y=kx
y=0.9(x)
plug and chug...
4(.9)=3.6
6(.9)= 5.4
12(.9)= 10.8