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lozanna [386]
3 years ago
13

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the dista

nce in 1.5 h. Car B traveled 15 mph faster than Car A. How fast did Car B travel? Enter your answer for the box.
___ mph

Mathematics
1 answer:
nikitadnepr [17]3 years ago
8 0
I hope this helps you

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Evaluate<br> 2^9 over 2^5
s2008m [1.1K]

Answer:

2^4  or 16

Step-by-step explanation:

We know that a^b / a^c = a^(b-c)

2^9 / 2^5

2^(9-5)

2^4  or 16

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3 years ago
A car is driving away from a crosswalk. The formula d = t2 + 2t expresses the car's distance from the crosswalk in feet, d, in t
alukav5142 [94]

Answer:

8 feet per second.

Step-by-step explanation:

We have been given that a car is driving away from a crosswalk. The formula d=t^2+2t expresses the car's distance from the crosswalk in feet, d, in terms of the number of seconds, t, since the car started moving.

We will use average change formula to solve our given problem.

\text{Average change}=\frac{f(b)-f(a)}{b-a}

\text{Average change}=\frac{d(5)-d(1)}{5-1}

\text{Average change}=\frac{(5)^2+2(5)-((1)^2+2(1))}{4}

\text{Average change}=\frac{25+10-(1+2)}{4}

\text{Average change}=\frac{35-3}{4}\\\\\text{Average change}=\frac{32}{4}\\\\\text{Average change}=8

Therefore, the the car's average speed over the given interval of time would be 8 feet per second.

8 0
3 years ago
Christine is 8 years younger than yuri. Express christine's age in terms of yuri's age
nikitadnepr [17]
Christine is “x” and yuri is “y”

y = x - 8
8 0
3 years ago
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