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lozanna [386]
3 years ago
13

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the dista

nce in 1.5 h. Car B traveled 15 mph faster than Car A. How fast did Car B travel? Enter your answer for the box.
___ mph

Mathematics
1 answer:
nikitadnepr [17]3 years ago
8 0
I hope this helps you

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The hourly median power (in decibels) of received radio signals transmitted between two cities
trasher [3.6K]

Using the lognormal and the binomial distributions, it is found that:

  • The 90th percentile of this distribution is of 136 dB.
  • There is a 0.9147 = 91.47% probability that received power for one of these radio signals is  less than 150 decibels.
  • There is a 0.0065 = 0.65% probability that for  6 of these signals, the received power is less than 150 decibels.

In a <em>lognormal </em>distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{\ln{X} - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of \mu = 3.5.
  • The standard deviation is of \sigma = \sqrt{1.22}

Question 1:

The 90th percentile is X when Z has a p-value of 0.9, hence <u>X when Z = 1.28.</u>

Z = \frac{\ln{X} - \mu}{\sigma}

1.28 = \frac{\ln{X} - 3.5}{\sqrt{1.22}}

\ln{X} - 3.5 = 1.28\sqrt{1.22}

\ln{X} = 1.28\sqrt{1.22} + 3.5

e^{\ln{X}} = e^{1.28\sqrt{1.22} + 3.5}

X = 136

The 90th percentile of this distribution is of 136 dB.

Question 2:

The probability is the <u>p-value of Z when X = 150</u>, hence:

Z = \frac{\ln{X} - \mu}{\sigma}

Z = \frac{\ln{150} - 3.5}{\sqrt{1.22}}

Z = 1.37

Z = 1.37 has a p-value of 0.9147.

There is a 0.9147 = 91.47% probability that received power for one of these radio signals is  less than 150 decibels.

Question 3:

10 signals, hence, the binomial distribution is used.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

For this problem, we have that p = 0.9147, n = 10, and we want to find P(X = 6), then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{10,6}.(0.9147)^{6}.(0.0853)^{4} = 0.0065

There is a 0.0065 = 0.65% probability that for  6 of these signals, the received power is less than 150 decibels.

You can learn more about the binomial distribution at brainly.com/question/24863377

5 0
2 years ago
Given a≠±b and a^2−b^2 / a+b =12, find a−b.
Olegator [25]

Answer:

a-b=12

Step-by-step explanation:

(a²-b²)/(a+b) = 12

(a-b)(a+b)/(a+b)=12

a-b=12

3 0
2 years ago
Please help me ASAP .......
mariarad [96]

Answer:

<3 ~= <5 - Alternate Interior Angles Theorem

<3 ~= <7 - Corresponding Angles Theorem

<5 ~= <7 - Vertical Angles Theorem

line I || line m - Transitive Property

3 0
3 years ago
On the first day, you pay $5 for 2 boxes of popcorn.
ahrayia [7]

Answer:

10 5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
My little sister needs help in this and I don't remember. ​
Anna71 [15]
You have to have the same denominator for both fractions, so I would multiply 3/4 by 3 that would give you 9/12 and the other one is 7/12. This means that the final answer would be 9/12>7/12.
7 0
2 years ago
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