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alexgriva [62]
4 years ago
13

5.) Find the value: -2/3 - (-2/5) =​

Mathematics
1 answer:
Citrus2011 [14]4 years ago
5 0

Answer: -4/15

Step-by-step explanation:

- 2/3 - (-2/5)

= -2/3 + 2/5

= -10/15 + 6/15

= -4/15

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Which statement best illustrates using the vertical line test to determine if the graph below is a function of x?
Ber [7]

Answer:

The answer is either a or c .

Step-by-step explanation:

3 0
3 years ago
-HELP ANSWER-
Doss [256]

Answer:

First point: (1,0)

Second Point: (2,1)

Third Point:  (3,2)

Fourth Point: (8,7)

Step-by-step explanation:

For the first two points, you have to plot the two pairs of coordinates that are given.  After this, you have to plug the x values into the equation to get the missing y values.

For example: The third point

X= 3

Y= X - 1

Y= 3 - 1

Y=2

So this means that the third coordinate is (3,2)


3 0
4 years ago
What is the length of the hypotenuse of a right triangle with legs that are 7 feet and 10 feet respectively?
zavuch27 [327]
7² + 10² = c² where c = hypotenuse

49 + 100 = c² 
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6 0
3 years ago
Read 2 more answers
If (12^5)^6=12^a, what is a <br><br> A=
dedylja [7]
So first simplify
(12^5)^6=(12^5)(12^5)(12^5)(12^5)(12^5)(12^5)
remember
if
(x^n)^m=x^nm
so
(12^5)^6=12^(5 times 6)=12^30

so 12^30=12^a
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3 0
4 years ago
Read 2 more answers
(4y^2-3y+2)+(5y+12y-4)-(13y^2-6y+20)
Andrews [41]

Answer:

-(9 y^2 - 20 y + 22) or if you need y = 10/9 + (7 i sqrt(2))/9 or y = 10/9 - (7 i sqrt(2))/9

Step-by-step explanation:

Simplify the following:

-(13 y^2 - 6 y + 20) + 4 y^2 + 12 y + 5 y - 3 y - 4 + 2

Grouping like terms, -(13 y^2 - 6 y + 20) + 4 y^2 + 12 y + 5 y - 3 y - 4 + 2 = -(13 y^2 - 6 y + 20) + 4 y^2 + (-3 y + 5 y + 12 y) + (2 - 4):

-(13 y^2 - 6 y + 20) + 4 y^2 + (-3 y + 5 y + 12 y) + (2 - 4)

-3 y + 5 y + 12 y = 14 y:

-(13 y^2 - 6 y + 20) + 4 y^2 + 14 y + (2 - 4)

2 - 4 = -2:

-(13 y^2 - 6 y + 20) + 4 y^2 + 14 y + -2

-(13 y^2 - 6 y + 20) = -13 y^2 + 6 y - 20:

-13 y^2 + 6 y - 20 + 4 y^2 + 14 y - 2

Grouping like terms, 4 y^2 - 13 y^2 + 14 y + 6 y - 20 - 2 = (-13 y^2 + 4 y^2) + (6 y + 14 y) + (-20 - 2):

(-13 y^2 + 4 y^2) + (6 y + 14 y) + (-20 - 2)

4 y^2 - 13 y^2 = -9 y^2:

-9 y^2 + (6 y + 14 y) + (-20 - 2)

6 y + 14 y = 20 y:

-9 y^2 + 20 y + (-20 - 2)

-20 - 2 = -22:

-9 y^2 + 20 y + -22

Factor -1 out of -9 y^2 + 20 y - 22:

Answer: -(9 y^2 - 20 y + 22)

______________________________________________

Solve for y:

-9 y^2 + 20 y - 22 = 0

Divide both sides by -9:

y^2 - (20 y)/9 + 22/9 = 0

Subtract 22/9 from both sides:

y^2 - (20 y)/9 = -22/9

Add 100/81 to both sides:

y^2 - (20 y)/9 + 100/81 = -98/81

Write the left hand side as a square:

(y - 10/9)^2 = -98/81

Take the square root of both sides:

y - 10/9 = (7 i sqrt(2))/9 or y - 10/9 = -(7 i sqrt(2))/9

Add 10/9 to both sides:

y = 10/9 + (7 i sqrt(2))/9 or y - 10/9 = -(7 i sqrt(2))/9

Add 10/9 to both sides:

Answer: y = 10/9 + (7 i sqrt(2))/9 or y = 10/9 - (7 i sqrt(2))/9

4 0
3 years ago
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