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Tems11 [23]
4 years ago
13

Determine which of the following formulas hold for all invertible n×n matrices A and B.

Mathematics
1 answer:
garik1379 [7]4 years ago
4 0

Answer:

1 hold

2 hold

3 does not hold

4 hold

5 hold

6 hold

7 does not hold

8 does not hold

9 Does not hold

10 Hold

Step-by-step explanation:

The detailed step by step verification is as shown in the attachment

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Please someone solve this, this is my third time reposting this question so yea please be quick
egoroff_w [7]

Answer:

Step-by-step explanation:

to calculate mean add all the entries in a week ,then divide by 7(the number of days)

i give you hint

mean for week 1=(52+65+...   +60)/7

8 0
3 years ago
If a car goes 40 miles per hour, how many minutes will it take for it to go 12 miles
dalvyx [7]

Answer:

18 minutes

Step-by-step explanation:

60/40=1.5

12 x 1.5 = 18

8 0
2 years ago
Read 2 more answers
A car travels 320 miles on 15 gasoline. The best estimate if the cars mile per gallon is
Dovator [93]

Answer:

21.333 miles per gallon

Step-by-step explanation:

3 0
4 years ago
Phyllis invested 50000 dollars, a portion earning a simple interest rate of 5 percent per year and the rest earning a rate of 7
Elodia [21]

Answer:

The amount invested at 5% was $39,000 and the amount invested at 7% was $11,000

Step-by-step explanation:

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

Let

x-----> the amount invested at 5%

50,000-x -----> the amount invested at 7%

so

t=1\ year\\ I=\$2,720\\r_1=0.05\\r_2=0.07\\P_1=\$x\\P_2=\$(50,000-x)

substitute in the formula above

2,720=x(0.05*1)+(50,000-x)(0.07*1)

solve for x

2,720=0.05x+3,500-0.07x

0.07x-0.05x=3,500-2,720\\0.02x=780\\x=\$39,000

(50,000-x)=\$11,000

therefore

The amount invested at 5% was $39,000 and the amount invested at 7% was $11,000

5 0
4 years ago
You are studying the relationship between the history of early childhood trauma (categorized as trauma/no trauma) and weight in
jeka57 [31]

Answer:

You can decide to <u>reject</u> the Null Hypothesis at p < 0.05.

Step-by-step explanation:

In this case, the relationship between the history of early childhood trauma and weight in adulthood are being studied.

The categories of childhood trauma are:

Trauma and No trauma.

So, number of rows is, <em>r</em> = 2.

The categories of weight in adulthood are:

Low to normal, Overweight, and Obese

So, number of columns is, <em>c</em> = 3.

The distribution of the statistic \chi^{2} is chi-square with (<em>r </em>- 1)(<em>c </em>- 1) degrees of freedom, where <em>r</em> represents the number of rows in the two-way table and <em>c</em> represents the number of columns.

Compute the degrees of freedom as follows:

df = (r-1)(c-1)=(2-1) \times (3-1) = 2

It is provided that the calculated value of Chi-square test statistic is 18.26.

Compute the <em>p</em>-value of the test as follows:

p-value=P(\chi^{2}_{2}\geq 18.26)\\=0.000108\\\approx0.00011

Decision rule:

The null hypothesis will be rejected if the <em>p</em>-value of the test is less than the significance level.

The significance level is, <em>α</em> = 0.05.

<em>p</em>-value = 0.00011 < <em>α</em> = 0.05.

The null hypothesis will be rejected at 5% level of significance.

Thus, the complete statement is:

"You can decide to <u>reject</u> the Null Hypothesis at p < 0.05."

4 0
3 years ago
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