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kirza4 [7]
3 years ago
5

At 5:00 a.m., the temperature outside was 66° F. By noon, the temperature had risen to 87° F. Which equation models the temperat

ure y at time x?
Mathematics
1 answer:
grigory [225]3 years ago
8 0
The answer I believe is y = 3x + 51

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35 points! Will mark Brainliest! Real answers only!
Olegator [25]

Answer:

Ty for the free poiunts!

Step-by-step explanation:

You got the answer right LLO

6 0
3 years ago
Read 2 more answers
Giving brainliest please help and understand this step by step
MA_775_DIABLO [31]

Answer:

3,813.33 \:  {cm}^{3}

Step-by-step explanation:

Volume of the space that is not occupied = Volume of cube shaped box - volume of soccer ball

=  {20}^{3}  -  \frac{4}{3}  \times 3.14 \times  {10}^{3}  \\  \\  = 8000 -  \frac{4}{3}  \times 3.14 \times  1000 \\  \\   = 8000 -  \frac{4}{3}  \times 3140 \\  \\  = 8000 -  \frac{12560}{3}  \\  \\  = 8000 - 4,186.66667 \\  \\  = 3,813.33333 \\  \\  = 3,813.33 \:  {cm}^{3}

5 0
3 years ago
Solve each system using elimination. tell whether the system has one solution, infinitely many solutions, or no solution.
Tomtit [17]
1.
x-2y=-1 \\
2x+y=4 \ \ \ |\times 2 \\ \\
x-2y=-1 \\
\underline{4x+2y=8 \ } \\
x+4x=8-1 \\
5x=7 \\
x=\frac{7}{5} \\
x=1 \frac{2}{5} \\ \\
x-2y=-1 \\
\frac{7}{5}-2y=-1 \\
-2y=-1-\frac{7}{5} \\
-2y=-\frac{5}{5}-\frac{7}{5} \\
-2y=-\frac{12}{5} \\
y=\frac{6}{5} \\
y=1 \frac{1}{5} \\ \\
\boxed{(x,y)=(1\frac{2}{5}, 1 \frac{1}{5}) \Leftarrow \hbox{one solution}}

2.
x+3y=4 \ \ \ |\times 2 \\
2x-6y=8 \\ \\
2x+6y=8 \\
\underline{2x-6y=8} \\
2x+2x=8+8 \\
4x=16 \\
x=4 \\ \\
x+3y=4 \\
4+3y=4 \\
3y=4-4 \\
3y=0 \\
y=0 \\ \\
\boxed{(x,y)=(4,0) \Leftarrow \hbox{one solution}}

3.
y=-\frac{1}{2}x-3 \ \ \ |\times (-2) \\
x+2y=-6 \\ \\
-2y=x+6 \\
\underline{x+2y=-6 \ } \\
x=x+6-6 \\
x-x=6-6 \\
0=0 \\ \\
\boxed{\hbox{infinitely many solutions}}

4.
6x-3y=-18 \\
-2x+4y=18 \ \ \ |\times 3 \\ \\
6x-3y=-18 \\
\underline{-6x+12y=54} \\
-3y+12y=54-18 \\
9y=36 \\
y=4 \\ \\
6x-3y=-18 \\
6x-3 \times 4=-18 \\
6x-12=-18 \\
6x=-18+12 \\
6x=-6 \\
x=-1 \\ \\
\boxed{(x,y)=(-1,4) \Leftarrow \hbox{one solution}}
3 0
3 years ago
NEED HELP ASAP 1 HOUR LEFT
katen-ka-za [31]

Using the vertex of a quadratic function, it is found that:

a) The revenue is maximized with 336 units.

b) The maximum revenue is of $56,448.

<h3>What is the vertex of a quadratic equation?</h3>

A quadratic equation is modeled by:

y = ax^2 + bx + c

The vertex is given by:

(x_v, y_v)

In which:

  • x_v = -\frac{b}{2a}
  • y_v = -\frac{b^2 - 4ac}{4a}

Considering the coefficient a, we have that:

  • If a < 0, the vertex is a maximum point.
  • If a > 0, the vertex is a minimum point.

The demand function is given by:

p(x) = 336 - 0.5x.

Hence, the revenue function is:

R(x) = xp(x)

R(x) = -0.5x² + 336x.

Which has coefficients a = -0.5, b = 336.

Hence, the value of x that maximizes the revenue, and the maximum revenue, are given, respectively, as follows:

  • x_v = -\frac{336}{2(-0.5)} = 336
  • y_v = -\frac{336^2 - 4(-0.5)(0)}{4(-0.5)} = 56448

More can be learned about the vertex of a quadratic function at brainly.com/question/24737967

#SPJ1

6 0
2 years ago
371 + 18x ≥ 566 solve for X
Andru [333]

18x \geqslant 566 - 371 \\ 18x \geqslant 195 \\  \frac{18x}{18}  \geqslant  \frac{195}{18}  \\ x \geqslant 10.8333333333

YOU CAN EVEN WRITE IT IN THE FRACTION FORM .

BE REMINDED THAT <> CHANGE SIGN WHEN YOU DIVIDE OR MULTIPLY A NEGATIVE NUMBER ONLY.

HOPE THIS HELPS

3 0
1 year ago
Read 2 more answers
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