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valentinak56 [21]
3 years ago
5

Thanks to all those who support my question!

Mathematics
2 answers:
Mazyrski [523]3 years ago
8 0

Answer:

no, because intergers are negative. they will never be able to be greater

Step-by-step explanation:

____ [38]3 years ago
6 0
No this is not possible
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Pls help me do these problems. I need them by today.
valina [46]

Answer:

see below

Step-by-step explanation:

Question 1: D

Question 2: A

Question 3: B

Question 4: B

Question 5: C

Question 6: D

Question 7: A

Question 8: D

5 0
2 years ago
Can someone please help me with this?
lutik1710 [3]

Answer:

(-78/29, -619/29)

Step-by-step explanation:

Since both equations are equal to y we can set them equal to each other

15x+19 = 1/2x - 20

Subtract 1/2x from each side

15x -1/2x +19 = -20

Subtract 19 from each side

14 1/2 x +19-19 = -20-19

Changing to an improper fraction

29/2 x = -38

Multiply each side by 2/29

x = 2/29 * -38

x = -78/29

Now find y

y = 1/2x - 20

y = 1/2 (-78/29) -20

y = -39/29 - 20

Get a common denominator

 =-39/20 - 580/29

 = -619/29

  -39/29 -580/29

8 0
3 years ago
In a right triangle, one of the acute angles measures 74°. What is the measure of the other acute angle?
Anika [276]

well, a right-triangle has 90° total, so if one of the acute angles is taking up 74°, then the other is just 90° - 74°.

5 0
3 years ago
Using 5 letters followed by 2 ​digits, how many passwords are​ possible?
Deffense [45]
Since there is no condition whatsoever for this arrangement, I can consider the 2 digits and the 5 letters as 7 different objects.

Total permutation (with no repetition):
7 chosen among 7 , that is 7 ! = 5040 arrangements

Total permutation (WITH REPERTITION):

7⁷ = 823 543

6 0
3 years ago
she sells 6adult tickets and 5 children tickets on the first day totaling $112.50 and on the second day she sells 8adult tickets
Leya [2.2K]

Answer:

Cost of adult ticket = $12.5

Cost of child ticket = $7.5

Step-by-step explanation:

Given:

Cost of 6 adult ticket and 5 child ticket = $112.5

Cost of 8 adult ticket and 4 child ticket = $130

Find:

Equation and solution

Computation:

Assume;

Cost of adult ticket = a

Cost of child ticket = b

So,

6a + 5b = 112.5....eq1

8a + 4b = 130 ......eq2

Eq2 x 1.25

10a + 5b = 162.5 .....eq3

eq3 - eq1

4a  = 50

Cost of adult ticket = $12.5

8a + 4b = 130

8(12.5) + 4b = 130

Cost of child ticket = $7.5

7 0
3 years ago
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