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Elis [28]
4 years ago
10

Does the midpoint BC lie on line AG? Why or why not?

Mathematics
2 answers:
lora16 [44]4 years ago
4 0

Answer:

D

Step-by-step explanation:

LenKa [72]4 years ago
3 0

Answer:

  see below

Step-by-step explanation:

Put the (x, y) values of point F into the equation for line AG and see if they work:

  y = (b/(a+c))x

For (x, y) = (a+c, b), this is ...

  b = (b/(a+c))(a+c) = b·(a+c)/(a+c) = b·1 = b . . . . . a true statement

Yes, F lies on line AG.

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By the equations according to the <em>cylindrical</em> system of coordinates, the equation for a helix are x = 8 · cos (2π · t /T), y = 8 · sin (2π · t /T) and z = 6 · (t/T).

<h3>How to derive the equations of a helix in cylindrical form</h3>

According to the <em>cylindrical</em> system of coordinates, helix can be described by the following equations:

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x = r · cos (2π · t /T)     (1)

y = r · sin (2π · t /T)      (2)

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Where T is the period of one <em>complete</em> revolution.

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x = 8 · cos (2π · t /T)

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4x -2y = 18 ______1

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from (1) make y the subject of formular

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