Question

Find the equations for a helix that has a radius of 8, a height of 12 and does exactly two complete revolutions (starting at the xy-plane).

Answer 1

By the equations according to the cylindrical system of coordinates, the equation for a helix are x = 8 · cos (2π · t /T), y = 8 · sin (2π · t /T) and z = 6 · (t/T).

How to derive the equations of a helix in cylindrical form

According to the cylindrical system of coordinates, helix can be described by the following equations:

Radius

x = r · cos (2π · t /T)     (1)

y = r · sin (2π · t /T)      (2)

Height

z = H · (t/T)     (3)

Where T is the period of one complete revolution.

If we know that r = 8 and H = 6, then the equations for the helix is:

x = 8 · cos (2π · t /T)

y = 8 · sin (2π · t /T)

z = 6 · (t/T)

How to learn more on helices: brainly.com/question/16911869

#SPJ1