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Lina20 [59]
3 years ago
6

Kristin jogs around a park that has a perimeter of 1/2 mile. Kristin jogged around the park 4 times in 50 minutes. What is the u

nit rate of Kristin's speed?
Mathematics
2 answers:
Leona [35]3 years ago
3 0

Kristin jogged at a unit rate of 4.2 miles an hour


Nitella [24]3 years ago
3 0
Kristin can jog around the park at a speed of: 0.04 miles a minute or: 1/25 of a mile a minute. 
1/2 times 4= 2 miles/50= 1/25 miles per minute

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Solve the following quadratic equation for all values of x in simplest form. (x-4)^2=33​
Brrunno [24]

\huge\text{$x=\boxed{\sqrt{33}+4,\ -\sqrt{33}+4}$}

To solve for x, we need to isolate it on one side of the equation.

Take the square root of both sides, making sure to use both positive and negative roots.

\begin{aligned}(x-4)^2&=33\\x-4&=\pm\sqrt{33}\end{aligned}

\sqrt{33} cannot be simplified, so we'll leave it as-is.

Add 4 to both sides to fully isolate x.

x=\pm\sqrt{33}+4

Expand the solution by making two solutions, one where \sqrt{33} is positive and one where it's negative.

x=\sqrt{33}+4,\ x=-\sqrt{33}+4\\x=\boxed{\sqrt{33}+4,\ -\sqrt{33}+4}

5 0
3 years ago
Read 2 more answers
What are the domain and range of the function f(x) = 3/4x + 5?
pantera1 [17]

Answer:

Domain = (-∞,∞)

Range = (-∞,∞)

This is a linear function.

So, if you were to graph this you'd know that it crosses the x and y axis and continues on forever without stopping.

in that case the domain and range are considered infinite on both axes.

3 0
3 years ago
Which of the following operations is true regarding relative frequency distributions? Multiple choice question. No two classes c
pshichka [43]

Answer:

The relative frequency is found by dividing the class frequencies by the total number of observations

Step-by-step explanation:

Relative frequency measures how often a value appears relative to the sum of the total values.

An example of how relative frequency is calculated

Here are the scores and frequency of students in a maths test

Scores (classes)              Frequency                Relative frequency

0 - 20                                10                               10 / 50 = 0.2

21 - 40                               15                               15 / 50 = 0.3

41 - 60                               10                               10 / 50 = 0.2

61 - 80                                5                                 5 / 50  = 0.1

81 - 100                             <u> 10</u>                                10 / 50 = <u>0.2</u>

                                          50                                               1

From the above example, it can be seen that :

  1. two or more classes  can have the same relative frequency
  2. The relative frequency is found by dividing the class frequencies by the total number of observations.
  3. The sum of the relative frequencies must be equal to one
  4. The sum of the frequencies and not the relative frequencies is equal to the number of observations.

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3 years ago
Which function is graphed? ​
Gennadij [26K]

Answer:

x-intercept=(-1,0) y-intercept =(0,-3)

Step-by-step explanation:

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Identify the equations as parallel lines, perpendicular lines, or neither.
IrinaVladis [17]
It is Perpendicular
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2 years ago
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