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2 years ago

Find the equation of the exponential function represented by the table

Mathematics

1 answer:

Rainbow [258]2 years ago

7 0

Answer:

y=-3.5x^2+9.5x-4

Step-by-step explanation:

y=a*x^2+b*x+c

4=0+0+c => c=-4

2=a+b-4 =>a+b=6

1=4a+2b-4 => 4a+2b=5

2a+b=2.5

a+b=6

a=-3.5

b=9.5

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How do you solve break even problems?

Mandarinka [93]

A break even problem is found when you calculate starting a buisieness
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8 0

2 years ago

The slope of the function ƒ (x) = 8 - 2x is _____. 2 - 2 8 -8

neonofarm [45]

Answer:

-2

Step-by-step explanation:

your equation is

f(x) = -2x+8

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4 0

2 years ago

Read 2 more answers

Use a double number line to answer Problem 1-5.

natita [175]

Answer:

900 cans and bottles.

Hope that helps!

Step-by-step explanation:

360 / 4 = 90

90 x 100 = 900

Hope that helps!

6 0

2 years ago

Which piece of additional information can be used to prove △CEA ~ △CDB?

Slav-nsk [51]

Answer-

The correct answer is

∠BDC and ∠AED are right angles

Solution-

In the ΔCEA and ΔCDB,

$m\angle BCD=m\angle ACE$

As this common to both of the triangle.

If ∠BDC and ∠AED are right angles, then $m\angle E=90=m\angle D$

Now as

∠BCD = ∠ACE and ∠BDC = ∠AED,

∠DBC and ∠EAC will be same. (as sum of 3 angles in a triangle is 180°)

Then, ΔCEA ≈ ΔCDB

Therefore, additional information can be used to prove ΔCEA ≈ ΔCDB is ∠BDC and ∠AED are right angles.

5 0

3 years ago

Read 2 more answers

The rate of change of the number of mountain lions N(t) in a population is directly proportional to 725 - N(t), where t is the t

wolverine [178]

Answer:

a) The implied differential equation is $\frac{dN}{725 - N} = kdt$

b) The general equation is $N = 725 - C e^{-kt}$

c) The particular equation is $N = 725 - 325 e^{-0.49t}$

d) The population when t = 5, N(5) = 697 = 700( to the nearest 50)

Step-by-step explanation:

The rate of change of N(t) can be written as dN/dt

According to the question, $\frac{dN}{dt} \alpha (725 - N(t))$

$\frac{dN}{dt} = k (725 - N)\\\frac{dN}{725 - N} = kdt$

Integrating both sides of the equation

$\int {\frac{1 }{725 - N}} \, dN = \int {k} \, dt\\- ln (725 - N) = kt + C\\ ln (725 - N) = -(kt + C)\\725 - N = e^{-(kt + C)} \\725 - N = e^{-kt} * e^{-C} \\725 - N = C e^{-kt}\\N = 725 - C e^{-kt}$