Ask question

Ask question

All categories

3 years ago

13

1. Calculate the length of the space diagonal of a block with dimensions:

1 answer:

Zolol [24]3 years ago

4 0

Given:

Dimensions of a block are w = 5 cm, l = 8 cm, h = 12 cm.

To find:

The length of the space diagonal of a block.

Solution:

Length of the diagonal is

$Diagonal=\sqrt{l^2+w^2+h^2}$

Putting the given values, we get

$Diagonal=\sqrt{(8)^2+(5)^2+(12)^2}$

$Diagonal=\sqrt{64+25+144}$

$Diagonal=\sqrt{233}$

$Diagonal=15.2643375...$

Round to the nearest tenth.

$Diagonal\approx 15.3$

So, the length of the space diagonal of a block is 15.3 cm.

Therefore, the correct option is B.

You might be interested in

This test will not impact your grade.

ycow [4]

Answer:

im pretty sure the distance is across the y and x axis

Step-by-step explanation:

5 0

3 years ago

Which is the solution set of 7y +1> 8y- 9?

fomenos

Answer:

y < 10 or (10, -∞)

Step-by-step explanation:

7y + 1 > 8y - 9

Simply get the y's on the right by subtracting 7y from both sides:

1 > y - 9

then adding 9 to both sides:

y < 10

or in interval notation:

(10, -∞)

7 0

3 years ago

A car that normally sells for $16,500 is now on sale for $14,000. What is the percent of discount? If necessary, round your answ

nika2105 [10]

Rounded, I believe it's 15%

8 0

3 years ago

Read 2 more answers

Solving Rational equations. LCD method. Show work. Image attached.

posledela

$(k-2)(k-6)=k^2-2k-6k+12=k^2-8k+12$

So in order to get all the fractions to have a common denominator, we need to multiply $\dfrac k{k-2}$ by $\dfrac{k-6}{k-6}$ , and $\dfrac1{k-6}$ by $\dfrac{k-2}{k-2}$ :

$\dfrac k{k-2}\cdot\dfrac{k-6}{k-6}=\dfrac{k(k-6)}{(k-2)(k-6)}=\dfrac{k^2-6k}{k^2-8k+12}$

$\dfrac1{k-6}\cdot\dfrac{k-2}{k-2}=\dfrac{k-2}{(k-2)(k-6)}=\dfrac{k-2}{k^2-8k+12}$

Now,

$\dfrac4{k^2-8k+12}=\dfrac{(k^2-6k)+(k-2)}{k^2-8k+12}$

As long as $k\neq2$ and $k\neq6$ (which we can't have because otherwise $k^2-8k+12=0$ ), we can cancel $k^2-8k+12$ in the denominators on both sides:

$4=(k^2-6k)+(k-2)$

$4=k^2-5k-2$

$0=k^2-5k-6$

We can factorize the right side:

$0=(k-6)(k+1)$

which tells us that $k=6$ and $k=-1$ are solutions.

4 0

3 years ago

One of the sides of a rectangle has length 7. Which of the following points, paired with (6,5), will make a side of this length?

TiliK225 [7]

Answer:

B (6,12)

Step-by-step explanation:

The distance from point A (6,5) to point B should be 7.

A- (6,5)-> (7,5) is 1 unit right

B- (6,5)-> (6,12) is 7 units up

C- (6,5)-> (6,7) is 2 units up

D- (6,5)-> (12,5) is 6 units up

6 0

3 years ago