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2 years ago

Please help How can you describe the graph of the equation y = mx? Explain

Mathematics

1 answer:

Mumz [18]2 years ago

6 0

Answer:

Every straight line can be represented by an equation: y = mx + b. ... The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-intercept. The y-intercept of this line is the value of y at the point where the line crosses the y axis.

Step-by-step explanation:

hope this helps.

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Ariel is working at meat -packing plant 5 night a weak .Her regular wage is $11 an hour.She earns time and a half for any overti

Bond [772]

Answer:

$148.50.

Step-by-step explanation:

Hourly wage for time and a half = 11 * 1.5

=$16.50

For 9 hours she earns 16.50 * 9

= $148.50.

4 0

2 years ago

How many terms are in this expression?<br><br> X + 1

DIA [1.3K]

Answer:

2 terms

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Prove the following by induction. In each case, n is apositive integer.<br> 2^n ≤ 2^n+1 - 2^n-1 -1.

frutty [35]

<h2>Answer with explanation:</h2>

We are asked to prove by the method of mathematical induction that:

$2^n\leq 2^{n+1}-2^{n-1}-1$

where n is a positive integer.

Let us take n=1

then we have:

$2^1\leq 2^{1+1}-2^{1-1}-1\\\\i.e.\\\\2\leq 2^2-2^{0}-1\\\\i.e.\\2\leq 4-1-1\\\\i.e.\\\\2\leq 4-2\\\\i.e.\\\\2\leq 2$

Hence, the result is true for n=1.

Let us assume that the result is true for n=k

i.e.

$2^k\leq 2^{k+1}-2^{k-1}-1$

Now, we have to prove the result for n=k+1

i.e.

<u>To prove:</u> $2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1$

Let us take n=k+1

Hence, we have:

$2^{k+1}=2^k\cdot 2\\\\i.e.\\\\2^{k+1}\leq 2\cdot (2^{k+1}-2^{k-1}-1)$

( Since, the result was true for n=k )

Hence, we have:

$2^{k+1}\leq 2^{k+1}\cdot 2-2^{k-1}\cdot 2-2\cdot 1\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{k-1+1}-2\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-2$

Also, we know that:

$-2$

(

Since, for n=k+1 being a positive integer we have:

$2^{(k+1)+1}-2^{(k+1)-1}>0$ )

Hence, we have finally,

$2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1$

Hence, the result holds true for n=k+1

Hence, we may infer that the result is true for all n belonging to positive integer.

i.e.

$2^n\leq 2^{n+1}-2^{n-1}-1$ where n is a positive integer.

6 0

3 years ago

Can someone please help me ASAP!¡

Nataliya [291]

1) No. 28/21 does not end up being equal to 2.
2) No. 45/5 does not equal 18/2
3) No. For something to be proportional, it should at least have the smaller number in the same place.
4) No. 25/12 does not equal 53/40
5) Yes. 4/2 is equal to 14/7
6) Yes. 4/1 is equla to 12/3
7) No. For something to be proportional, it should at least have the smaller number in the same place.
8) No. 44/9 is not equal to 36/11
9) Yes. 10/5 is equal to 16/8
10) Yes. 24/12 is equal to 14/7
11) No. 24/4 is not equal to 42/9
12) Yes. Both equal 1.
13) Yes. 20/5 is equal to 44/11
14) No. 44/40 is not equal to 34/30
15) Yes . 40/4 is equal to 10/1
16) Yes. 36/4 is equal to 45/5
17) No. 16/2 is not equal to 13/1
18) No. 38/9 is not equal to 28/7
19) Yes. This is a common proportion.
20) Yes. 50/25 is equal to 2.
21) Yes. 36/24 is equal to 3/2.
22) Yes. 18/12 is equal to 42/28
23) No. 33/42 is not equal to 27/37
24) No. 34/7 is not 4
25) Yes. The second proportion listed is half of the first
26) Yes. This is proportional.
27) Yes. This is proportional.
28) Yes. This is proportional.
29) No. This is not proportional.
30) No. This is not proportional
31) Yes. This is proportional.
32) Yes. This is proportional
33)
34)
35)
36)
37)
38)
39)
40)
I hope this helped. I left the last few unsolved so you could follow the patterns to find them out!

3 0

3 years ago

What value of x would make the figure a parallelogram (show your math please)

Verdich [7]

Answer:

Step-by-step explanation:

Diagonals of a parallelogram bisects each other.

Therefore,

4x = 8

x = 8/4

x = 2

5x = 3x + 4

5x - 3x = 4

2x = 4

x = 4/2

x = 2

8 0

2 years ago