Let's assume
It started in 2000
so, t=0 in 2000

we can use formula

we can plug value

In 2005, the same survey was made and the total amount of gamma ray bursts was 7.3 million
so, at t=2005-2000=5
P(t)=7.3 million
we can plug value and then we can solve for r


now, we can plug back

now, we have
P(t)=1 billion =1000 million
so, we can set it and then we can solve for t


approximately

Year is 2000+192
year is 2192................Answer
Answer:

Step-by-step explanation:
<u>Given Second-Order Homogenous Differential Equation</u>

<u>Use Auxiliary Equation</u>
<u />
<u>General Solution</u>
<u />
Note that the DE has two distinct complex solutions
where
and
are arbitrary constants.
Answer:
it is irrational,because the product of an irrational number and a non zero rational number is irrational
Answer:
x = 4 or x = -1
Step-by-step explanation:
2x^2 - 8x + 6 =0
divide by 2 we get : x^2 -4x +3 = 0
(x -4) (x+1)
x = 4 or x = -1