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irinina [24]
3 years ago
11

Please help me with this

Mathematics
1 answer:
elena55 [62]3 years ago
5 0
Budding plants, hope this helps :)
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Brianna bought 5 bananas for 1 dollar. Sal bought 5 bananas at $.49 a pound. If a banana weighs about 5 ounces, who got the bett
vfiekz [6]

Answer:

Sal

Step-by-step explanation:

4 0
3 years ago
How long dose it take to travel 5km at an average speed of 8 m/s? Give your answers in minutes and seconds
eduard

Answer:

625 seconds and 10 minutes

Step-by-step explanation:

distancs=S=5km=5000m

average speed=v=8m/s

time taken=t=?

as we know that

average speed=\frac{distance covered}{time taken}

average speed×time taken=distance covered

here we have to find the time taken

time taken=\frac{distance covered}{average speed}

time taken=\frac{5000m}{8m/s}

time taken=625seconds

now we convert seconds into minutes

\frac{625}{60}

10 minutes

4 0
3 years ago
Nelson middle school raise $19,950 on ticket sales for it's carnival fundraiser last year at $15 per ticket. If the school sells
Snowcat [4.5K]
19950/15=1330 they sold 1,330 tickets last year
1330*20=26600
if they sold the same amount of tickets as they did last year for $20 they would have 26,600 in sales.
3 0
3 years ago
SOMEONE PLEASE HELP MEEEEE
natka813 [3]

Answer:

Area = 23.12 cm²

perimeter = 24.28 cm

Step-by-step explanation:

top shaded region is circular arc with 90° sector angle

so perimeter of arc is 90 / 360 * 2πr

here radius of arc is half the length of square side

r = 6.8/2 = 3.4

top area shaded perimeter = 90/360 * 2 * 3.14 * 3.4

= 1/4 * 2 * 3.14 * 3.4

= 5.338

bottom region perimeter is also same

total perimeter of shaded region is = side + side + two arcs

= 6.8 + 6.8 + 2 * 5.338

= 13.6 + 10.676

= 24.276

= 24.28

Area of top shaded region is 90/360 * πr²

A = 1/4 * 3.14 * 3.4²

= 9.0746

bottom shaded region area is half of area of square - area of bottom arc

= 6.8 * 3.4  - 9.0746

= 23.12 - 9.0746

= 14.0454

so total area of shaded region is 9.0746 + 14.0454

= 23.12

or you can just calculate area as half of area of total square = 6.8² / 2

= 23.12

8 0
3 years ago
The function f (x comma y )equals 3 xy has an absolute maximum value and absolute minimum value subject to the constraint 3 x sq
zmey [24]

Answer:

The maximum value of f is 363, which is reached in (11,11) and (-11,-11) and the minimum value of f is -33, which is reached in (√11,-√11) and (-√11,√11)

Step-by-step explanation:

f(x,y) = 3xy, lets find the gradient of f. First lets compute the derivate of f in terms of x, thinking of y like a constant.

f_x(x,y) = 3y

In a similar way

f_y(x,y) = 3x

Thus,

\nabla{f} = (3y,3x)

The restriction is given by g(x,y) = 121, with g(x,y) = 3x²+3y²-5xy. The partial derivates of g are

[ŧex] g_x(x,y) = 6x-5y [/tex]

g_y(x,y) = 6y - 5x

Thus,

\nabla g(x,y) = (6x-5y,6y-5x)

For the Langrange multipliers theorem, we have that for an extreme (x0,y0) with the restriction g(x,y) = 121, we have that for certain λ,

  • f_x(x_0,y_0) = \lambda \, g_x(x0,y0)
  • f_y(x_0,y_0) = \lambda \, g_y(x_0,y_0)
  • g(x_0,y_0) = 121

This can be translated into

  • 3y = \lambda (6x-5y)
  • 3x = \lambda (-5x+6y)
  • 3 (x_0)^2 + 3(y_0)^2 - 5\,x_0y_0 = 121

If we sum the first two expressions, we obtain

3x + 3y = \lambda (x+y)

Thus, x = -y or λ=3.

If x were -y, then we can replace x for -y in both equations

3y = -11 λ y

-3y = 11 λ y, and therefore

y = 0, or λ = -3/11.

Note that y cant take the value 0 because, since x = -y, we have that x = y = y, and g(x,y) = 0. Therefore, equation 3 wouldnt hold.

Now, lets suppose that λ=3, if that is the case, we can replace in the first 2 equations obtaining

  • 3y = 3(6x-5y) = 18x -15y

thus, 18y = 18x

y = x

and also,

  • 3x = 3(6y-5x) = 18y-15x

18x = 18y

x = y

Therefore, x = y or x = -y.

If x = -y:

Lets evaluate g in (-y,y) and try to find y

g(-y,y) = 3(-y)² + 3y*2 - 5(-y)y = 11y² = 121

Therefore,

y² = 121/11 = 11

y = √11 or y = -√11

The candidates to extremes are, as a result (√11,-√11), (-√11, √11). In both cases, f(x,y) = 3 √11 (-√11) = -33

If x = y:

g(y,y) = 3y²+3y²-5y² = y² = 121, then y = 11 or y = -11

In both cases f(11,11) = f(-11,-11) = 363.

We conclude that the maximum value of f is 363, which is reached in (11,11) and (-11,-11) and the minimum value of f is -33, which is reached in (√11,-√11) and (-√11,√11)

5 0
3 years ago
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