(<span>−v</span>)<span>(p)</span>+40<95
−<span>pv</span>+40+<span>−40</span><<span>95+<span>−40</span></span>
−<span>pv</span><<span>55</span>
<span>-pv/-p < 55/-p</span>
<span>v > -55/p</span>
<span> your final answer is -55/p</span>
If I am reading the equation correctly, I do not believe it has a solution.
Fill in the point values in the formula for the derivative.
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<u>Example</u>
y = x^2 + 3x . . . . . we want y' at (x, y) = (1, 4)
y' = 2x +3 . . . . . . . take the derivative dy/dx of the function
Fill in the value x=1 ...
y' = 2·1 +3 = 5
The value of the derivative at (x, y) = (1, 4) is 5.
The frequency for this problem would me x2 every time you add on to the chart or go down the chart good luck:)
