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lesya692 [45]
3 years ago
7

Carlos’s family had breakfast at one restaurant and dinner at another restaurant while on vacation. The service during breakfast

was terrible and the cost for the meal was $44.50. Carlos’s total bill (cost of meal and tip) was $49.84. The service during dinner was excellent and the cost for the meal was $57.50.
a. What was the percentage of the tip for breakfast?



b. Carlos decided the tip’s percentage for dinner should be 50% more than the tip’s percentage for breakfast. What percent did Carlos give for a tip during dinner?



c. What was the amount of the tip and the total bill (cost of meal and tip) for dinner using the percentage of the tip from part b?
Mathematics
1 answer:
OleMash [197]3 years ago
8 0
To solve part a, do the following.
49.84-44.50=<span>5.34
5.34/44.50=x/100
after solving the proportion, x would be equal to 12.
To solve part b, do the following.
50+12=62
</span>To solve part c, do the following.
The amount of the tip is:
x/<span>57.50=62/100
which is </span><span>35.65
The total bill is:
35.65+</span>57.50=<span>93.15</span>
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Answer:

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The population of organism A doubles every day, geometrically as follows

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The population after 5 days, is therefore;

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The virus cuts the population in half for three days as follows;

The first of ta·2⁵ he three days = 32/2 = 16·a

The second of the three days = 16/2 = 8·a

After the third day, Pₐ = 8/2 = 8·a

The population growth of organism B is the same as the initial growth of organism A, therefore, the population, P₈ of organism B after 8 days is given as follows;

P₈ =  a·2⁸ = 256·a

Therefore, the number of times organism B's population is larger than organism A's population after 8 days is P₈/Pₐ = 256·a/8·a = 32 times

Which gives, the number of times organism B's population is larger than organism A's population after 8 days is 32 times.

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Madisyn is planting crops in a triangular garden. She is trying to find the amount of fencing
MrRissso [65]

Answer:

Fencing needed = 20.8 units

Step-by-step explanation:

From the figure attached,

Given: Triangle ABC with vertices A(0, 6), B(6, 5) and C(5, -1).

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Amount of fencing required = Perimeter of the triangular garden

Perimeter of the garden = AB + BC + AC

Formula to get the distance between A and B,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AB = \sqrt{(0-6)^2+(6-5)^2} = \sqrt{37}

BC = \sqrt{(6-5)^2+(5+1)^2} = \sqrt{37}

AC = \sqrt{(0-5)^2+(6+1)^2} = \sqrt{74}

Perimeter = \sqrt{37}+\sqrt{37}+\sqrt{74}

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