This graph has a horizontal asymptote so it is an exponential graph. It also passes through two points (0,-2) and (1,3). The horizontal asymptote is at y=-3.
The unchanged exponential equation is y=a(b)^x +k
For exponential equations, k is always equal to the horizontal asymptote, so k=-3.
You can check this with the ordered pair (0,-2). After that plug in the other ordered pair, (1,3).
This gives you 3=a(b)^1 or 3=ab. If you know the base the answer is simple as you just solve for a.
If you don't know the base at this point you have to sort of guess. For example, let's say both a and b are whole numbers. In that case b would have to be 3, as it can't be 1 since then the answer never changes, and a is 1. Then choose an x-value and not exact corresponding y-value. In this case x=-1 and y= a bit less than -2.75. Plug in the values to your "final" equation of y=(3)^x -3.
So -2.75=(3^-1)-3.
3^-1 is 1/3, 1/3-3 is -8/3 or -2.6667 which is pretty close to -2.75. So we can say the final equation is y=3^x -3.
Hope this helps! It's a lot easier to solve problems like these given either more points which you can use system of equations with, or with a given base or slope.
Answer:
16.80 euros.
Step-by-step explanation:
12% = 0.12
So it will now be 15 + 15 * 0.12
= 16.80.
Population of moose in the national park = 240
percentage increase in the population of moose in the national park after a year = 25%
Then
Amount of increase in the population
Of moose in the national park in a year = (25/100) * 240
= 240/4
= 60
So
The number of moose present after 1 year
in the national park = 240 + 60
= 300
So from the above deduction we can easily conclude that the number of moose in the national park after a year is 300.
Answer:
Range is y > 0
Step-by-step explanation:
We need to find the range of y = e^4x
The range is defined as a set of values of dependent variable for which the function is defined.
The exponential function of form c. n^x + k has range f(x) > k
in the given function y = e^4x ,k =0
so Range is y > 0
What is the question
tell me please