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Assoli18 [71]
3 years ago
13

The doctor ordered 800,000 units of a particular drug for a patient. The drug comes in a solution of 2,000,000 units per 10 cc.

How many cc should the nurse give the patient.
Mathematics
1 answer:
dalvyx [7]3 years ago
5 0

Answer:

199,200,000

Step-by-step explanation:

idk if thats correct hope it helps

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A recursive rule for a geometric sequence is
LuckyWell [14K]

Answer:

C. a_n=(9)(\frac{2}{3})^{n-1}

Step-by-step explanation:

Iterative geometric sequence:

a_n=a_1x^{n-1}

Recursive geometric sequence:

a_n=xa_{n-1}

The equations are very similar and you only really need to rearrange it. The factor (2/3) and the first term (9) are given, so you can write the iterative equation:

a_n=(9)(\frac{2}{3})^{n-1}

And so the answer is C.

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2 years ago
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0.07 as a mixed number
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5 0
3 years ago
given examples of relations that have the following properties 1) relexive in some set A and symmetric but not transitive 2) equ
rodikova [14]

Answer: 1) R = {(a, a), (а,b), (b, a), (b, b), (с, с), (b, с), (с, b)}.

It is clearly not transitive since (a, b) ∈ R and (b, c) ∈ R whilst (a, c) ¢ R. On the other hand, it is reflexive since (x, x) ∈ R for all cases of x: x = a, x = b, and x = c. Likewise, it is symmetric since (а, b) ∈ R and (b, а) ∈ R and (b, с) ∈ R and (c, b) ∈ R.

2) Let S=Z and define R = {(x,y) |x and y have the same parity}

i.e., x and y are either both even or both odd.

The parity relation is an equivalence relation.

a. For any x ∈ Z, x has the same parity as itself, so (x,x) ∈ R.

b. If (x,y) ∈ R, x and y have the same parity, so (y,x) ∈ R.

c. If (x.y) ∈ R, and (y,z) ∈ R, then x and z have the same parity as y, so they have the same parity as each other (if y is odd, both x and z are odd; if y is even, both x and z are even), thus (x,z)∈ R.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial but not transitive, so the relation provided in (1) satisfies this condition.

Step-by-step explanation:

1) By definition,

a) R, a relation in a set X, is reflexive if and only if ∀x∈X, xRx ---> xRx.

That is, x works at the same place of x.

b) R is symmetric if and only if ∀x,y ∈ X, xRy ---> yRx

That is if x works at the same place y, then y works at the same place for x.

c) R is transitive if and only if ∀x,y,z ∈ X, xRy∧yRz ---> xRz

That is, if x works at the same place for y and y works at the same place for z, then x works at the same place for z.

2) An equivalence relation on a set S, is a relation on S which is reflexive, symmetric and transitive.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial and not transitive.

QED!

6 0
3 years ago
Find the maximum number of children to whom 30 sweaters and 45 trousers can be equally divided. Also find out how many sweaters
Vinvika [58]

Answer:

15 children can divide them with eachother, each get 2 sweaters and 3 trousers

Step-by-step explanation:

15×2=30

15×3=45

7 0
3 years ago
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