<span>We want to optimize f(x,y,z)=x^2 y^2 z^2, subject to g(x,y,z) = x^2 + y^2 + z^2 = 289.
Then, ∇f = λ∇g ==> <2xy^2 z^2, 2x^2 yz^2, 2x^2 y^2 z> = λ<2x, 2y, 2z>.
Equating like entries:
xy^2 z^2 = λx
x^2 yz^2 = λy
x^2 y^2 z = λz.
Hence, x^2 y^2 z^2 = λx^2 = λy^2 = λz^2.
(i) If λ = 0, then at least one of x, y, z is 0, and thus f(x,y,z) = 0 <---Minimum
(Note that there are infinitely many such points.)
(f being a perfect square implies that this has to be the minimum.)
(ii) Otherwise, we have x^2 = y^2 = z^2.
Substituting this into g yields 3x^2 = 289 ==> x = ±17/√3.
This yields eight critical points (all signage possibilities)
(x, y, z) = (±17/√3, ±17/√3, ±17/√3), and
f(±17/√3, ±17/√3, ±17/√3) = (289/3)^3 <----Maximum
I hope this helps! </span><span>
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Answer:
When you divide one number by another, the result is called the quotient. This is true for rational expressions too! When you divide one rational expression by another, the result is called the quotient.
Answer:
- 20 + 8i
Step-by-step explanation:
Noting that i² = - 1
Given
[(6i + 9) + (4i - 5)] × 2i ← evaluate the terms inside the square bracket
= ( 6i + 9 + 4i - 5 ) × 2i
= (10i + 4) × 2i ← multiply each term in the parenthesis by 2i
= 20i² + 8i
= 20(- 1) + 8i
= - 20 + 8i
That means that head was the most one to appear than tails
