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3 years ago

Find the positive solution of x when: 25 = 4/x²

1 answer:

7 0

1) Multiply both sides by x²

$25 {x}^{2} \: = \: 4$

2) Divide both sides by 25

${x}^{2} \: = \: \frac{4}{25}$

3) Square root both sides

$x \: = \: \frac{2}{5}$

Viola!

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Pleas Help Due Tomorrow must SHOW WORK

Arturiano [62]

Answer:

42 degrees

Step-by-step explanation:

180-138 = 42

angles 1, 2, and 5 are all 139 degrees

angles 7, 3, 4, and 6 are 42 degrees

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3 years ago

Read 2 more answers

A laser beam is transmitted with a "width" of .0008 degrees and

pickupchik [31]

Answer:

Object will be at a distance of 358098.6 km from the source

Step-by-step explanation:

We have given angle = 0.0008 degree $=\frac{0.0008\times \pi }{180}=4.444\times 10^{-6}\pi$

Radius is given = 2.50 km

Linear size of the object will be equal to diameter

So linear size = 2.5×2 = 5 km

We know that linear size $=distance \times \Theta$

So $5=d\times 4.444\times 10^{-6}\pi$

d = 358098.6 km

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3 years ago

What is algebra 1 and 2

telo118 [61]

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3 years ago

Consider the planes 4x+3y+4z=1 and 4x+4z=0. (A) Find the unique point P on the y−axis which is on both planes. ( 0 equation edit

Nana76 [90]

Answer:

Step-by-step explanation:

A) From the order of the exercise we already know that the intersection points lies on the Y-axis, so its coordinates are P(0;y;0). In order to find it, we only need to substitute the equation 4x+4z=0 into the equation 4x+3y+4z=1. Then,

1=4x+3y+4z = 3y + (4x+4z)= 3y+0.

From the expression above it is easy to obtain that y=1/3, and the intersection point is P(0;1/3;0).

B) To obtain the parallel vector to both planes we use the cross product of the normal vector of the planes.

$\left[\begin{array}{ccc}i&j&k\\4&3&4\\4&0&4\end{array}\right] = 12i-0j+12k$

As we want a unit vector, we must calculate the modulus of u:

$|u|=\sqrt{12^2+0^2+12^2} = \sqrt{2\cdot 12^2}=12\sqrt{2}$ .

Thus, the wanted vector is $\frac{u}{12\sqrt{2}}$ . Therefore,

$u = \frac{1}{\sqrt{2}}i-\frac{1}{\sqrt{2}}k = \frac{\sqrt{2}}{2}i-\frac{\sqrt{2}}{2}k$ .

C) In order to obtain the vector equation of the intersection line of both planes, we just need to put together the above results.

$r = \frac{1}{3}j +\lambda \left( \frac{\sqrt{2}}{2}i- \frac{\sqrt{2}}{2}k \right)$

where $\lambda$ is a real number.

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4 years ago

64^x = 16^ x - 1 A: -2 B: -1 C: -1/4 D: -1/3

Murljashka [212]

Answer:

Step-by-step explanation:

64/3

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3 years ago