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3 years ago

Find the positive solution of x when: 25 = 4/x²

1 answer:

7 0

1) Multiply both sides by x²

$25 {x}^{2} \: = \: 4$

2) Divide both sides by 25

${x}^{2} \: = \: \frac{4}{25}$

3) Square root both sides

$x \: = \: \frac{2}{5}$

Viola!

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Can some one plzzz help me

-BARSIC- [3]

Answer:

Step-by-step explanation:

Since we are given that f(x)=1, we just have to find what value of x gives 1 as the result.

From the graph, we can see that (0,1) gives 1 as a y-value. Thus, when x is 0, y is 1.

Therefore, f(0)=1.

So, our answer is B.

And we're done!

8 0

3 years ago

Robert is 10 years older than her brother. In 2 years, Robert will be three times as old as his brother. How old are they now?

valentina_108 [34]

Robert is 13 and his brother is 3 y.o.
X... brother’s age
X+10... Robert’s age
X+10+2... Robert’s age in 2 years
X+2...Brother’s age in 2 years
X+10+2/x+2=3
X=3
X+10=13

6 0

3 years ago

WILL GIVE BRIANLEST!!!!!!!!

Elenna [48]

Answer:

3ft * 8ft

Step-by-step explanation:

The base of the pyramid is the rectangle, and the rectangle has the dimensions of 3ft * 8ft.

7 0

2 years ago

Read 2 more answers

I need help pleaseeeeeee D:

mamaluj [8]

Car A: 24.8 Miles per gallon.
Car B: 21 Miles per gallon
Car C: 18.75 Miles per gallon

Car A is the answer. Make sure when you are putting work you multiply each number at the start of this answer with 0.62. That'll be how many Kilometers per gallon. Just divide the amount of Miles by the gallons for unit rate.

3 0

3 years ago

The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t

shtirl [24]

Answer:

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

Step-by-step explanation:

As the given Augmented matrix is

$\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 1 :

$r_{1}$ ↔ $r_{1} - r_{2}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 2 :

$r_{3}$ ↔ $r_{3} - 8r_{1}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]$

Step 3 :

$r_{2}$ ↔ $\frac{r_{2}}{7}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]$

Step 4 :

$r_{1}$ ↔ $r_{1} + 14r_{2}$ , $r_{3}$ ↔ $r_{3} - 124r_{2}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]$

Step 5 :

$r_{3}$ ↔ $\frac{r_{3}. 7}{254}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]$

Step 6 :

$r_{1}$ ↔ $r_{1} - 4r_{3}$ , $r_{2}$ ↔ $r_{2} + \frac{1}{7} r_{3}$

$\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]$

∴ we get

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

6 0

3 years ago