F(x) = 4 [cos (x)]^2 - 3 = 0
4[cos(x)]^2 = 3
cos(x) = √3 / 2
That happens in the first and fourth quadrants, for the angles 30 degrees and 330 degrees.
Answer: x = 30 degrees and x = 330 degrees
Answer:
The length of side b is 179 ft
Step-by-step explanation:
Given triangle ABC in which
∠A = 33°, ∠B = 63°, c=200
we have to find the length of b
In ΔABC, by angle sum property of triangle
∠A+∠B+∠C=180°
33°+63°+∠C=180°
∠C=180°-33°-63°=84°
By sine law,
![\frac{\sin \angle A}{a}=\frac{\sin \angle B}{b}=\frac{\sin \angle C}{c}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csin%20%5Cangle%20A%7D%7Ba%7D%3D%5Cfrac%7B%5Csin%20%5Cangle%20B%7D%7Bb%7D%3D%5Cfrac%7B%5Csin%20%5Cangle%20C%7D%7Bc%7D)
![\frac{\sin \angle B}{b}=\frac{\sin \angle C}{c}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csin%20%5Cangle%20B%7D%7Bb%7D%3D%5Cfrac%7B%5Csin%20%5Cangle%20C%7D%7Bc%7D)
![\frac{\sin 63^{\circ}}{b}=\frac{\sin 84^{\circ}}{200}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csin%2063%5E%7B%5Ccirc%7D%7D%7Bb%7D%3D%5Cfrac%7B%5Csin%2084%5E%7B%5Ccirc%7D%7D%7B200%7D)
![b=200\times \frac{\sin 63^{\circ}}{\sin 84^{\circ}}=179.182887\sim 179 ft](https://tex.z-dn.net/?f=b%3D200%5Ctimes%20%5Cfrac%7B%5Csin%2063%5E%7B%5Ccirc%7D%7D%7B%5Csin%2084%5E%7B%5Ccirc%7D%7D%3D179.182887%5Csim%20179%20ft)
The length of side b is 179 ft
Option C is correct.
Answer:
Pretty sure 25%.
Step-by-step explanation:
First, you would need to see how many times 60 goes into 100, because a percent is ALWAYS over 100. You should get an answer of 1.66666667. Then you if you multiply it to one of the numbers then you have to do it to the other number. So, you would do 15 times 1.66666667. You would get 25. So, that would be 25 over 100 or 25/100. And 25 over 100 is 25%.
I hope I helped! :) Sorry if it's wrong :(
Answer:
10.85
Step-by-step explanation:
2x + 1.5x x=3.1
simply plugg in <em>3.1 for X</em>
2 multiplied by 3.1 + 1.5 multiplied by 3.1 and you get
6.2 + 4.65 which = 10.85