11 squared is 121
20 squared is 400
121+400= 521
The approximate square root of 521 is approximately 22.8254
Here’s a picture of my work. The answer is b. Hope this helps :-)
Let set C = {1, 2, 3, 4, 5, 6, 7, 8} and set D = {2, 4, 6, 8}.
g100num [7]
<span>1. If it is intersection then it SHOULD be included in both the sets right?
Now we know that odd numbers from 1-100 but the second set are multiples of 5 from 50-150! So we mainly need to look for common numbers which are ODD and are a MULTIPLE OF 5 BETWEEN 50 - 100!!
So
A={51,53,57,59,61......99}
B={55,60,65,70.......95} [We stop till 100 because set A has no such element]
So what is A ∩ B here?
A ∩ B = {All odd numbers and multiples of 5 between 50 - 100}
</span>
Answer:
4 cm
Step-by-step explanation:
Both the area of a square and the area of a rectangle can be found by multiplying length x width. Because all of the sides of a square are equal, you get 64 when you multiply two sides together to find the area.
Since the rectangle has the same area as the square, that means the rectangle's width has to be a number that equals 64 when multiplied by 16.
So, 64/16 equals 4.
Please mark as brainliest ;)
Circle A would make more sense (I'm not exactly sure) because it shows the entire circle (if you know what I mean).
