All categories

3 years ago

Surface area of a cylinder with a radius of 7cm and a height of 12

Mathematics

2 answers:

Keith_Richards [23]3 years ago

7 0

Answer:

CSA = 2 * pi * r * h

Step-by-step explanation:

CSA = 2 * 22 * 7 * 12 / 7

= 2 * 22 * 12

528 cm ^3

olya-2409 [2.1K]3 years ago

7 0

Answer:

$The~surface ~area~of~this~cylinder~is~835.66cm^2.$

Step-by-step explanation:

$Greetings!$

$I'm~Isabelle~Williams~and~will~be~answering~your~question!$

$To~find~the~surface~of~a~cylinder,~we~use~the~formula~that~is:$

$\boxed{~A=2\pi r ~h+2\pi r^2~}$

$In~our~case~we~have:$

$=2\times \pi \times 7\times 12+2\times \pi \times 7^2$

$=835.66cm^2$

$Thus,~the~surface~area~of~this~cylinder~is~835.66cm^2.$

$Hope~this~helps~and~have~an~amazing~day~ahead!$

$-Isabelle~Williams$

You might be interested in

what equation is solved by the graphed systems of equations? Two linear equations that intersect at the point negative 1, negati

alexgriva [62]

Answer:

1. The equation is solved by the graphed systems of equations is:

Third option: 7x + 3 = x − 3

2. The solution to the system is:

Fourth option: (3,-1)

3. The graph of the system y = −2x + 3 and 2x + 4y = 8 is:

Third option: Line through point (0, 3) and (1, 1). Line through (0, 2) and (4, 0).

4. The solution to the system is:

Second option: Infinite solutions.

5. Bill will have read the same amount of books as Mandy in:

Fourth option: December

Step-by-step explanation:

Question 1. What equation is solved by the graphed systems of equations?

Two linear equations that intersect at the point (-1, -4)=(x,y)→x=-1, y=-4

a. 7x + 3 = x + 3

Solving for x: Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

7x+3-x=x+3-x

6x+3=3

Subtracting 3 both sides of the equation:

6x+3-3=3-3

6x=0

Dividing both sides of the equation by 6:

6x/6=0/6

Dividing:

x=0 different to the intersection at x=-1, then this is not the equation.

b. 7x − 3 = x − 3

Solving for x: Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

7x-3-x=x-3-x

6x-3=-3

Adding 3 both sides of the equation:

6x-3+3=-3+3

6x=0

Dividing both sides of the equation by 6:

6x/6=0/6

Dividing:

x=0 different to the intersection at x=-1, then this is not the equation.

c. 7x + 3 = x − 3

Solving for x: Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

7x+3-x=x-3-x

6x+3=-3

Subtracting 3 both sides of the equation:

6x+3-3=-3-3

6x=-6

Dividing both sides of the equation by 6:

6x/6=-6/6

Dividing:

x=-1 equal to the intersection at x=-1, then this is the equation.

d. 7x − 3 = x + 3

Solving for x: Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

7x-3-x=x+3-x

6x-3=3

Adding 3 both sides of the equation:

6x-3+3=3+3

6x=6

Dividing both sides of the equation by 6:

6x/6=6/6

Dividing:

x=1 different to the intersection at x=-1, then this is not the equation.

Question 2 (Multiple Choice Worth 2 points) (06.03) Solve the system 2x + 3y = 3 and 3x − 2y = 11 by using graph paper or graphing technology. What is the solution to the system?

The solution to the system is (3, -1) Fourth option

Please, see the attached graph.

Question 3 (Multiple Choice Worth 2 points) (06.03) What is the graph of the system y = −2x + 3 and 2x + 4y = 8?

Third option: Line through point (0, 3) and (1, 1). Line through (0, 2) and (4, 0).

Please, see the attached graph.

Question 4 (Multiple Choice Worth 2 points) (06.03) Solve the system y = 3x + 2 and 3y = 9x + 6 by using graph paper or graphing technology. What is the solution to the system?

Second option: Infinite solutions.

Please, see the attached graph.

Question 5 (Multiple Choice Worth 2 points) (06.03) At the end of April, Mandy told Bill that she has read 16 books this year and reads 2 books each month. Bill wants to catch up to Mandy. He tracks his book reading with a table on his door. Using his table below, what month will Bill have read the same amount of books as Mandy?

Bill

Month Books

May 4

June 8

July 12

August 16

September 20

October 24

November 28

December 32

Books read by Mandy: y=16+2x

Numbers of months since april: x

May: x=1→y=16+2(1)=16+2→y=18 different to 4 (books read by Bill)

June: x=2→y=16+2(2)=16+4→y=20 different to 8 (books read by Bill)

July: x=3→y=16+2(3)=16+6→y=22 different to 12 (books read by Bill)

September: x=5→y=16+2(5)=16+10→y=26 different to 20 (books read by Bill)

October: x=6→y=16+2(6)=16+12→y=28 different to 24 (books read by Bill)

November: x=7→y=16+2(7)=16+14→y=30 different to 28 (books read by Bill)

December: x=8→y=16+2(8)=16+16→y=32 equal to 32 (books read by Bill)

Answer. Fourth option: December

4 0

3 years ago

PLEASE ANSWER FAST

Lina20 [59]

The square root of 16 is 4

7 0

3 years ago

Read 2 more answers

William bought some tickets to see his favorite singer. He bought some adult tickets and some children’s tickets, for a total of

Fantom [35]

Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.

8 0

3 years ago

Please i need help asap

svetlana [45]

Answer:

She spaced them out one block more on each side. She needs to move B one more block closer to make this illustration genuine:

B(4)

I am joyous to assist you anytime.

5 0

3 years ago

What is 42789 x 54678

vichka [17]

42789 times 54678
is 2,339,616,942

Show Work:
Calculate 9 x 8, which is 72.
Since 72 is two-digit, we carry the first digit 7 to the next column.

3 Calculate 8 x 8, which is 64. Now add the carry digit of 7, which is 71.
Since 71 is two-digit, we carry the first digit 7 to the next column.

4 Calculate 7 x 8, which is 56. Now add the carry digit of 7, which is 63.
Since 63 is two-digit, we carry the first digit 6 to the next column.


5 Calculate 2 x 8, which is 16. Now add the carry digit of 6, which is 22.
Since 22 is two-digit, we carry the first digit 2 to the next column.

6 Calculate 4 x 8, which is 32. Now add the carry digit of 2, which is 34.
Since 34 is two-digit, we carry the first digit 3 to the next column.

7 Bring down the carry digit of 3.

8 Calculate 9 x 7, which is 63.
Since 63 is two-digit, we carry the first digit 6 to the next column.

9 Calculate 8 x 7, which is 56. Now add the carry digit of 6, which is 62.
Since 62 is two-digit, we carry the first digit 6 to the next column.

10 Calculate 7 x 7, which is 49. Now add the carry digit of 6, which is 55.
Since 55 is two-digit, we carry the first digit 5 to the next column.

11 Calculate 2 x 7, which is 14. Now add the carry digit of 5, which is 19.
Since 19 is two-digit, we carry the first digit 1 to the next column.

12 Calculate 4 x 7, which is 28. Now add the carry digit of 1, which is 29.
Since 29 is two-digit, we carry the first digit 2 to the next column.


13 Bring down the carry digit of 2.

14 Calculate 9 x 6, which is 54.
Since 54 is two-digit, we carry the first digit 5 to the next column.

15 Calculate 8 x 6, which is 48. Now add the carry digit of 5, which is 53.
Since 53 is two-digit, we carry the first digit 5 to the next column.


16 Calculate 7 x 6, which is 42. Now add the carry digit of 5, which is 47.
Since 47 is two-digit, we carry the first digit 4 to the next column.


17 Calculate 2 x 6, which is 12. Now add the carry digit of 4, which is 16.
Since 16 is two-digit, we carry the first digit 1 to the next column.


18 Calculate 4 x 6, which is 24. Now add the carry digit of 1, which is 25.
Since 25 is two-digit, we carry the first digit 2 to the next column.


19 Bring down the carry digit of 2.


20 Calculate 9 x 4, which is 36.
Since 36 is two-digit, we carry the first digit 3 to the next column.

21 Calculate 8 x 4, which is 32. Now add the carry digit of 3, which is 35.
Since 35 is two-digit, we carry the first digit 3 to the next column.

22 Calculate 7 x 4, which is 28. Now add the carry digit of 3, which is 31.
Since 31 is two-digit, we carry the first digit 3 to the next column.

23 Calculate 2 x 4, which is 8. Now add the carry digit of 3, which is 11.
Since 11 is two-digit, we carry the first digit 1 to the next column.

24 Calculate 4 x 4, which is 16. Now add the carry digit of 1, which is 17.
Since 17 is two-digit, we carry the first digit 1 to the next column.

25 Bring down the carry digit of 1.

26 Calculate 9 x 5, which is 45.
Since 45 is two-digit, we carry the first digit 4 to the next column.

27 Calculate 8 x 5, which is 40. Now add the carry digit of 4, which is 44.
Since 44 is two-digit, we carry the first digit 4 to the next column.

28 Calculate 7 x 5, which is 35. Now add the carry digit of 4, which is 39.
Since 39 is two-digit, we carry the first digit 3 to the next column.

29 Calculate 2 x 5, which is 10. Now add the carry digit of 3, which is 13.
Since 13 is two-digit, we carry the first digit 1 to the next column.

30 Calculate 4 x 5, which is 20. Now add the carry digit of 1, which is 21.
Since 21 is two-digit, we carry the first digit 2 to the next column.

31 Bring down the carry digit of 2.

32 Calculate 342312 + 2995230 + 25673400 + 171156000 + 2139450000, which is 2339616942

6 0

3 years ago

Read 2 more answers

Surface area of a cylinder with a radius of 7cm and a height of 12​

Surface area of a cylinder with a radius of 7cm and a height of 12