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Dahasolnce [82]
3 years ago
10

Surface area of a cylinder with a radius of 7cm and a height of 12​

Mathematics
2 answers:
Keith_Richards [23]3 years ago
7 0

Answer:

CSA = 2 * pi * r * h

Step-by-step explanation:

CSA = 2 * 22 * 7 * 12 / 7

= 2 * 22 * 12

528 cm ^3

olya-2409 [2.1K]3 years ago
7 0

Answer:

The~surface ~area~of~this~cylinder~is~835.66cm^2.

Step-by-step explanation:

Greetings!

I'm~Isabelle~Williams~and~will~be~answering~your~question!

To~find~the~surface~of~a~cylinder,~we~use~the~formula~that~is:

\boxed{~A=2\pi r ~h+2\pi r^2~}

In~our~case~we~have:

=2\times \pi \times 7\times 12+2\times \pi \times 7^2

=835.66cm^2

Thus,~the~surface~area~of~this~cylinder~is~835.66cm^2.

Hope~this~helps~and~have~an~amazing~day~ahead!

-Isabelle~Williams

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Mademuasel [1]

Answer and explanation:

1. 9:12 or \frac{9}{12} or 9 to 12

It has 9 first because there are 9 lions and then 12 after because there are 12 elephants.

2. 8:16 or \frac{8}{16} or 8 to 16

It has 8 first because there are 8 giraffes and then 16 after because there are 16 otters.

3. 9:10 or \frac{9}{10} or 9 to 10

It has 9 first because there are 9 lions and then 10 after because there are 10 seals.

4. 10:12 or \frac{10}{12} or 10 to 12

It has 10 first because there are 10 seals and then 12 after because there are 12 elephants.

5. 12:9 or \frac{12}{9} or 12 to 9

It has 12 first because there are 10 elephants and then 9 after because there are 9 lions.

6. \frac{8}{6} or \frac{40}{30} or \frac{16}{12}

I just multiplied it first the first one by 2, second one by 10, and 3rd one by 4.

7. \frac{6}{7} or \frac{42}{49} or \frac{60}{70}

I just simplified it first, then I multiplied the simplified one by 6 for the second one, and for the 3rd one I multiplied the simplified by 10.

8. \frac{2}{3} or \frac{4}{6} or \frac{20}{30}

I just simplified it first, then I multiplied the simplified one by 2 for the second one, and for the 3rd one I multiplied the simplified by 10.

9. 3:4 is equivalent to 6:8, 30:40, 12:16

I multiplied it first by 2, then by 10, then by 4.

10. 5:7 is equivalent to 10:14, 50:70, 25:35

I multiplied it first by 2, then by 10, then by 5.

11. 9:2 is equivalent to 18:4, 90:20, 27:6

I multiplied it first by 2, then by 10, then by 3.

12.

a. 48

So first, the ratio we know is 5:4 which in other words is 5x:4x. We also know that there are 60 clownfish. So that means 5x = 60 --> x = 12. So then 4x has to equals 12 x 4 which is 48.

b. 36

So first, the ratio we know is 4:3 which in other words is 4x:3x. We also know that there are 48 angelfish. So that means 4x = 48 --> x = 12. So then 3x has to equals 12 x 3 which is 36.

Hope this helped! <3

8 0
2 years ago
Solve: y = -7(-13)<br> it said 21 was wrong
White raven [17]

Answer: y = 91

Step-by-step explanation:

y = -7(-13)

y = -7 x -13

y = 91

4 0
2 years ago
A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t
11Alexandr11 [23.1K]

Answer:

  • <u>Question 1:</u>      dm/dt=0.2m<u />

<u />

  • <u>Question 2:</u>     m=Ae^{(0.2t)}<u />

<u />

  • <u>Question 3:</u>      m=10e^{(0.2t)}<u />

<u />

  • <u>Question 4:</u>      m=10g<u />

Explanation:

<u>Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m</u>

<u></u>

a) By definition:  m'=dm/dt

b)  Given:  rate=0.2m

c) By substitution:  dm/dt=0.2m

<u>Question 2: Find the general solution of this equation. Use A as a constant of integration.</u>

a) <u>Separate variables</u>

     dm/m=0.2dt

b)<u> Integrate</u>

           \int dm/m=\int 0.2dt

            ln(m)=0.2t+C

c) <u>Antilogarithm</u>

       m=e^{0.2t+C}

       m=e^{0.2t}\cdot e^C

         e^C=A\\\\m=Ae^{(0.2t)}

<u>Question 3. Which particular solution matches the additional information?</u>

<u></u>

Use the measured rate of 4 grams per hour after 3 hours

            t=3hours,dm/dt=4g/h

First, find the mass at t = 3 hours

            dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g

Now substitute in the general solution of the differential equation, to find A:

          m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976

Round A to 1 significant figure:

  • A = 10.

<u>Particular solution:</u>

           

             m=10e^{(0.2t)}

<u>Question 4. What was the mass of the bacteria at time =0?</u>

Substitute t = 0 in the equation of the particular solution:

         m=10e^{0}\\\\m=10g

3 0
3 years ago
5+3r=5r-19(if there is no solution,type in ''no solution'')r= Answer
TEA [102]

Answer: 12 = r

Step-by-step explanation: When we have this kind of a setup, we want to put our variables together on one side of the equation and our numbers together on the other side of the equation.

First, let's put our variables on the right side by subtracting 3r from both sides of the equation. That gives us 5 = 2r - 19.

Now we can move our numbers to the left by adding 19 to both sides of the equation and we get 24 = 2r.

Divide both sides by 2 and 12 = r

Note:

Don't just do this problem in your head. It's extremely important to develop the habit of putting all your steps down on paper or digitally. It will really pay off for you down the line.

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