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Alexus [3.1K]
3 years ago
6

Tropical rainforests have many species that are found in great abundance. A study in the Brazilian rainforest found 487 tree spe

cies growing on a single hectare (2.5 acres). In the US and Canada together, there are only 700 species of trees on millions of acres. In one park in a Peruvian rainforest, scientists have identified over 1300 species of butterflies, while in all of Europe there are approximately 320 butterfly species. These findings suggest that:
A. rainforests are biologically less diverse than other ecosystems on earth.
B. the number of tree species and butterfly species are about the same throughout the ecosystems of the world.
C. rainforests are biologically more diverse than other ecosystems.
D. as many as 400 species a day are lost due to human activity.
E. rainforests do not have any type of value to humans.
Biology
1 answer:
Yuri [45]3 years ago
6 0
C: rainforest are biologically more diverse than ecosystems.

Explanation: the reason why this is correct is because of the vast ratio of American and Europeans animal/plant species compared to Brazil alone. They have much more diversity hence having more biodiversity. The vast amount of plants and animals are superior to other countries.
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In horses, black color(B) dominates chestnut color(b). The trotting gait(T) dominates the pacing gait (t). A cross is made betwe
bulgar [2K]

Answer:

<h2>a.  BbTt;</h2><h2>b. BbTt X BbTt ;</h2><h2> Parent 1: BT bt Bt bT </h2><h2> Parent 2: BT bt Bt bT ;</h2><h2>c. BBTT , BbTt , BBTt , BbTT , BbTt , BbTt , BBTt , BbTT , BBTt , Bbtt , BBtt , BbTt , BbTT , bbTt , BbTt , bbTT.</h2><h2> d. 12:1:1:2</h2>

Explanation:

As given Block color is dominant over chesnut color, so B is dominant over b.

Chestnut color=bb ;

Trotting gait is dominant over  pacing gait, so T is dominant over t .

Pacing gait=tt

Now;  cross between

(a) homozygous black, pacing gait is= BBtt; and horse homozygous for chestnut color, trotting gait is= bbTT

BBtt x bbTT

gametes are ; Bt and bT,

Progeny are BbTt, BbTt,

All progeny will be BbTt  heterozygous Black color and heterozygous trotting gait

b. a cross is made between two horses, both of who are heterozygous black trotter = BbTt X BbTt

 Possible gametes of each parent are;

Parent 1: BT bt Bt bT

Parent 2: BT bt Bt bT

c.  Punnett square and  all the possible gene combinations that results are;

Cross between these gametes

BT bt Bt bT

BT bt Bt bT

possible gene combinations ; BBTT , BbTt , BBTt , BbTT , BbTt , BbTt , BBTt , BbTT , BBTt , Bbtt , BBtt , BbTt , BbTT , bbTt , BbTt , bbTT.

d. expected phenotype ration of the offspring.

Black color and trotting gait  horse 12: chestnut and trotting gait horse 1: Black color pacing gait horse  1: chestnut and trotting gait  horse 2.

so 12:1:1:2

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Explanation:

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A cat and a dog cannot produce fertile offspring because they are not the same_____
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