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densk [106]
3 years ago
8

Paul is the web page designer for his company. Paul’s boss tells him that customers have been complaining that it is difficult t

o read the text on the company’s web page. Paul’s boss asks him to solve the issue by increasing the legibility of the text on the web page. What is the best way Paul can improve the legibility? Eliminate background elements within 128 pixels of text elements. Modify the CSS of the page to display all elements in absolute position. Change the text to a very dark color and the background to a very light color. Decrease the overall contrast between the text and the background.
Computers and Technology
2 answers:
dsp733 years ago
7 0

Answer:

Generally speaking, the fastest way to improve legibility on a webpage is to increase the contrast of the text and the background or "Change the text to a very dark color and the background to a very light color".

Explanation:

It is c the light and dark make it easier to read

ra1l [238]3 years ago
6 0

Answer:

Who is paul

Explanation:

2+2 =4 -1 =3 quick mats

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Answer:

Dennis Ritchie

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The instructions in a program, when expressed in Python, ...
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Explanation:

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2 years ago
A. Requiring computer users to log off before leaving for lunch
GuDViN [60]

Answer:

Option A, B, and D.

Explanation:

In the above question, the some details of the question are missing that is the part of the question.

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3 years ago
Which of the following is not included in the manufacturing industry cluster?
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To reduce the number of used digital outputs of the microcontroller, the display board is connected to the main board through th
Luda [366]

Answer:

The program in Python is as follows:

BCD = ["0001","0010","0011","0100","0101","0110","0111"]

num = input("Decimal: ")

BCDValue = ""

valid = True

for i in range(len(num)):

   if num[i].isdigit():

       if(int(num[i])>= 0 and int(num[i])<8):

           BCDValue += BCD[i]+" "

       else:

           valid = False

           break;

   else:

       valid = False

       break;

if(valid):

   print(BCDValue)

else:

   print("Invalid")

Explanation:

This initializes the BCD corresponding value of the decimal number to a list

BCD = ["0001","0010","0011","0100","0101","0110","0111"]

This gets input for a decimal number

num = input("Decimal: ")

This initializes the required output (i.e. BCD value)  to an empty string

BCDValue = ""

This initializes valid input to True (Boolean)

valid = True

This iterates through the input string

for i in range(len(num)):

This checks if each character of the string is a number

   if num[i].isdigit():

If yes, it checks if the number ranges from 0 to 7 (inclusive)

       if(int(num[i])>= 0 and int(num[i])<8):

If yes, the corresponding BCD value is calculated

           BCDValue += BCD[i]+" "

       else:

If otherwise, then the input string is invalid and the loop is exited

<em>            valid = False</em>

<em>            break;</em>

If otherwise, then the input string is invalid and the loop is exited

<em>    else:</em>

<em>        valid = False</em>

<em>        break;</em>

If valid is True, then the BCD value is printed

<em>if(valid):</em>

<em>    print(BCDValue)</em>

If otherwise, it prints Invalid

<em>else:</em>

<em>    print("Invalid")</em>

7 0
3 years ago
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