If my calculations are correct the answer is cut your answer in half
Answer:
We are 95% confident that the average weight of the heaviest egg that is still medium size is 3.52 oz
Step-by-step explanation:
Mean = 3.2 oz, sd = 0.13 oz
Assuming there are 3 heavy eggs, n= 3, degree of freedom = n-1 = 3-1 = 2, t-value corresponding to 2 degrees of freedom and 95% confidence level is 4.303
Error margin = t×sd/√n = 4.303×0.13/√3 = 0.32 oz
Upper limit (heaviest egg that is still medium size) = mean + error margin = 3.2 + 0.32 = 3.52 oz
5(n-4)=(4n-12)
First: Distribute 5 into n and -4.
5(n-4)=(5n)+(5*-4)= 5n-20.
Second: Subtract 4n from both sides to eliminate the variable from the right side of the equation.
(5n-20)=(4n-12)
n-20=-12
Next: Add 20 to both sides to eliminate the constant from the left side of the equation.
n-20=-12
n=8
The unknown number is 8.
Answer: I don’t get it
Step-by-step explanation:
8,000 or 08,080?
