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yarga [219]
2 years ago
8

Consider right triangle MNO below which expression represents the length of side MN

Mathematics
1 answer:
mafiozo [28]2 years ago
7 0

Answer:

by the Pythagoras theorem ....

which is :

(NO)^2 + (OM)^2 = (NM)^2

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Each letter of the word ASSESSMENT is written on a card and placed in a bag. You are equally likely to get any card.
NARA [144]

Answer:

I would say getting four S would be more percent than the other letters in the assessment word. They have more chance, and more possibility.

Step-by-step explanation: Brainliest please

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3 years ago
13 divided by $85.02
Salsk061 [2.6K]
The answer is 0.15290519877
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Find the length of the missing side
faltersainse [42]

Answer:

c = 17

Step-by-step explanation:

Since this is a right angle triangle we can use the Pythagoras theorem that states that c^{2} = a^{2} + b^{2} (where c is the Solve for  hypotenuse and "a" and "b" are the legs of the right angle triangle). From here we know that the answer to this question is....

c^{2} = a^{2} + b^{2}\\c^{2} = 15^{2} + 8^{2} \\c^{2} = 225 + 64\\c^{2} = 289\\c = \sqrt{289} \\c = 17

6 0
3 years ago
What is the slope of the equation-3=-4(x-5)
scZoUnD [109]
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5 0
3 years ago
To two decimal places, find the value of k that will make the function f(x) continuous everywhere. f of x equals the quantity 3x
Fiesta28 [93]

Given function is

f(x)=\left\{\begin{matrix}3x+k & x\leq -4 \\ kx^2-5 & x> -4\end{matrix}\right.

now we need to find the value of k such that function f(x) continuous everywhere.

We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.

So we just need to find both left and right hand limits then set equal to each other to find the value of k

To find the left hand limit (LHD) we plug x=-4 into 3x+k

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To find the Right hand limit (RHD) we plug x=-4 into

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Now set both equal

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15k=-7

k=-\frac{7}{15}

k=-0.47

<u>Hence final answer is -0.47.</u>




7 0
3 years ago
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