Answer: 193.3125
Step-by-step explanation:
It deleted my entire explanation um-
Anyways, calculate the area of the rectangle, length x width (7 * 15) and the semicircle (i did pi times radius squared and halved it to get the semicircle)
Basically, 105 plus the semicircle is 193.
Answer:
in steps
Step-by-step explanation:
DE // BC
m∠ADE = m∠ABC and m∠AED = m∠ACB
∴ ΔADE similar to ΔABC
AB/AD = AC/AE
(AD + DB) / AD = (AE + EC) / AE
AD/AD + DB/AD = AE/AE + EC/AE
1 + DB/AD = 1 + EC/AE
DB/AD = EC/AE (AD/DB = AE/EC)
For a better understanding of the solution provided here, please find the diagram attached.
In the diagram, ABCD is the room.
AC is the diagonal whose length is 18.79 inches.
The length of wall AB is 17 inches.
From the given information, we have to determine the length of the BC, which is depicted a
, because for the room to be a square, the length of the wall AB must be equal to the length of the wall BC.
In order to determine the length of the wall BC, or
, we will have to employ the Pythagoras' Theorem here. Thus:


Thus,
inches
and hence, the given room is not a square.
Answer:
262.6/300% for the first 3 test if you were to add another test it would be 400% total and you need 360% of test grades to have an average of 90% and so 360 - 262.6 = 97.4%
Step-by-step explanation:
Ok to start you have to put
2+-1/9 - 4+-1/3
what exactly is the question because without the proper info. nobody is going to be able to figure it out.