3( x - y )^2 - 2( x - y ) =
<em>(</em><em> </em><em>x</em><em> </em><em>-</em><em> </em><em>y</em><em> </em><em>)</em><em> </em>( 3( x - y) - 2 ) =
( x - y )( 3x - 3y - 2 )
Answer:
(-2 , 5)
(-1 , 0)
(1 , -4)
(3 , 0)
(4 , -5)
Step-by-step explanation:
<u>First solve the equation:</u>
x² - 2x - 3
<em><u>Find two numbers with have a sum of -2 and a product of -3.</u></em>
-3 and 1
(x - 3)(x + 1)
Solve for x:
x - 3 = 0
x = 3
x + 1 = 0
x = -1
You know that the graph will cross the x-axis at -1 and 3.
(-1 , 0)
(3 , 0)
You know that the graph is positive.
<u>Complete the square to find the vertex</u>
x² - 2x - 3
(x - 1)² = x² - 2 + 1
x² - 2x - 3 = x² - 2 + 1 - 2 = (x - 1)² - 2
1 = 0
x = 1
Substitute into the original equation:
x² - 2x - 3 =
1² - (2 * 1) - 3 =
1 - 2 - 3 =
-4
(1 , -4)
<em><u>You can input any two numbers within -10 and 10. Such as -2 and 4.</u></em>
x² - 2x - 3 =
-2² - (2 * -2) - 3 =
4- -4- 3 =
5
(-2 , 5)
x² - 2x - 3 =
4² - (2 * 4) - 3 =
16 - 8 - 3 =
-5
(4 , -5)
Not Rationally, No. But You Can Make It Into 26.5
Find the domain by finding where the function is defined. The range is the set of values that correspond with the domain.
Domain: (- infinity, infinity)
Range: (- infinity, -2)
Answer:
The first incorrect justification is in step 2.
Step-by-step explanation:
<u>Step 2</u>. BC2 = AC • DC
2. BC ÷ DC = BC ÷ AC because triangle ABC is similar to triangle BDC
It's supposed to be AC ÷ BC not BC ÷ AC.
