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Ira Lisetskai [31]
3 years ago
14

Solve for y ax+by=c help asap

Mathematics
1 answer:
jekas [21]3 years ago
7 0
ax + by = c\\\\by = c - ax\\\\\boxed{y = \frac{c-ax}{b}}
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Mr. Smith ordered 27 boxes of baseballs. There were 30 baseballs in each box. How many baseballs did Mr. Smith order?
kirill115 [55]

Answer:

27x30=810

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
HELP ‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️WILL MARK BRAINLYEST‼️‼️‼️
Rainbow [258]

Answer:

8 one-dollar bills

3 five-dollar bills

2 ten-dollar bills

Step-by-step explanation:

Let x = # of one-dollar bills, y = # of five-dollar bills, and z = # of ten-dollar bills. Total amount in the wallet is $43, so the first equation would be 1x + 5y + 10z = 43. Next, there are 4 times as many one-dollar bills as ten-dollar bills, so x = 4z. There are 13 bills in total, so x + y + z = 13

x + 5y + 10z = 43

x = 4z

x + y + z = 13

x + 5y + 10z = 43

x + 0y - 4z = 0

x + y + z = 13

5y + 14z = 43

-y - 5z = -13

5y + 14z = 43

-5y - 25z = -65

-11z = -22

z = 2

x = 4z

x = 4*2 = 8

x + y + z = 13

8 + y + 2 = 13

10 + y = 13

y = 3

3 0
2 years ago
The lowest point in Death Valley is Badwater at 282 feet below sea level. The highest point in
Finger [1]

Answer:

Step-by-step explanation:

Given

Badwater = -282ft

Telescope\ Peak = 11043ft

The position of badwater is negated because it is below sea level

The interpretation of the question, is to calculate the distance between the two given points.

This is calculated as:

Difference = Telescope\ Peak - Badwater

Difference = 11043ft - (-282ft)

Open bracket

Difference = 11043ft+282ft

Difference = 11325ft

<em>Hence, the distance between both is 11325ft</em>

8 0
3 years ago
Determine if the following relations are functions. if they are functions, also state the domain and range.
Feliz [49]

Answer:

no, they are not functions

Step-by-step explanation:

this is because a single domain has multiple range.

i.e. domain 2 has ranges 2 and 4

4 0
3 years ago
Use the Law of Cosines to find the missing angle. In triangle JKL, j=3in., k=4in., and l=2.89., find mJ
slega [8]
Using the law of cosine for Triangle KJL, we can write:

j^{2} = k^{2} + l^{2}-2(k)(l)cos(J)  \\  \\ &#10;2(k)(l)cos(J)=k^{2} + l^{2}- j^{2} \\  \\ &#10;cos(J)= \frac{k^{2} + l^{2}- j^{2}}{2(k)(l)}

Using the values of k,j and l, we can write:

cos(J)= \frac{ 4^{2} + (2.89)^{2} - 3^{2} }{2(4)(2.89)}  \\  \\ &#10;cos(J)= 0.664 \\  \\ &#10;J= cos^{-1}(0.664) \\  \\ &#10;J=48.39

Rounding to nearest integer, the measure of angle J will be 48 degrees.
So option B gives the correct answer
8 0
3 years ago
Read 2 more answers
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