Answer:
0.4114  
0.0006  
0.1091  
0.1957  
Step-by-step explanation:
<u>Given:  </u>
p = 0.7 n = 10 
We need to determine the probabilities using table , which contains the CUMULATIVE probabilities P(X  x).
 x).  
a. The probability is given in the row with n = 10 (subsection x = 3) and in the column with p = 0.7 of table:  
P(X  3) = 0.4114
  3) = 0.4114  
b. Complement rule:  
P( not A) = 1 - P(A) 
Determine the probability given in the row with n = 10 (subsection x = 10) and in the column with p = 0.7 of table:  
P(X  10) = 0.9994
  10) = 0.9994 
Use the complement rule to determine the probability:  
P(X > 10) = 1 - P(X 10) = 1 - 0.9994 = 0.0006
 10) = 1 - 0.9994 = 0.0006  
c. Determine the probability given in the row with n = 10 (subsection x = 5 and x = 6) and in the column with p = 0.7 of table:  
P(X  5) = 0.8042
  5) = 0.8042 
P(X  6) = 0.9133
  6) = 0.9133 
The probability at X = 6 is then the difference of the cumulative probabilities:  
P(X = 6) = P(X  6) - P(X
  6) - P(X  5) = 0.9133 — 0.8042 = 0.1091
  5) = 0.9133 — 0.8042 = 0.1091  
d. Determine the probability given in the row with n = 10 (subsection x = 5 and x = 11) and in the column with p = 0.7 of table:  
P(X  5) = 0.8042
  5) = 0.8042 
P(X  11) = 0.9999
  11) = 0.9999 
The probability at 6  X
 X  11 is then the difference between the corresponding cumulative probabilities:
 11 is then the difference between the corresponding cumulative probabilities:  
P(6  X
  X  11) = P(X
 11) = P(X  11) - P(X
 11) - P(X  5) = 0.9999 — 0.8042 = 0.1957
  5) = 0.9999 — 0.8042 = 0.1957